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MakcuM [25]
4 years ago
8

A 3.5-m3 rigid tank initially contains air whose density is 2 kg/m3 . The tank is connected to a high-pressure supply line throu

gh a valve. The valve is opened, and air is allowed to enter the tank until the density in the tank rises to 6.5 kg/m3 . Determine the mass of air that has entered the tank.
Engineering
1 answer:
Mumz [18]4 years ago
6 0

Answer:

Explanation:

First, we find the mass of the air originally in the tank.

Density is given as mass divided by volume. It is given as:

Density = \frac{mass}{volume}

Therefore, mass is:

mass = denisty *volume

Density of air = 2 kg/m^3; Volume of the tank =  3.5 m^3

=> Mass = 3.5 * 2 = 7 kg

The mass of the air initially in the tank is 7 kg.

After air is allowed to enter, the mass changes.

New density = 6.5 kg/m^3

The new mass will be:

Mass = 6.5 * 3.5 = 22.75 kg

We can now find the mass of air that has entered the tank:

Mass of air that entered tank = New mass of air - Original mass of air

M = 22.75 - 7.0 = 15.75 kg

The mass of air that entered the tank is 15.75 kg.

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Answer & Explanation:

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NISA [10]

This question is incomplete, the complete question is;

Find the magnitude of the steady-state response of the system whose system model is given by

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Answer: The steady state output x(t) = 0.2481 cos( 8t - 45° )

Explanation:

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dx(t)/dt + x(t) = f(t)  where f(t) = 2cos8t

dx(t)/dt + x(t) = f(t)

we apply Laplace transformation on both sides

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therefore The steady state output x(t) = 0.2481 cos( 8t - 45° )

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3 years ago
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