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Answer & Explanation:
//written in java
public class Main {
public static void main(String[] args) {
//declare a char variable for a, b, c
char a;
char b;
char c;
//assign a b and c
//a b and c can be replaced for with
// '#', '$', '%', then with '1', '2', '3'
// for further testing
a = 'x';
b = 'y';
c = 'z';
//output for all possible combination for a, b, c.
System.out.println("" + a + b + c + " " + a + c + b + " " + b + a + c +
" " + b + c + a + " " + c + a + b + " " + c + b + a);
}
}
Pretty sure the answer is A
DescriptionOperant conditioning is a type of associative learning process through which the strength of a behavior is modified by reinforcement or punishment. It is also a procedure that is used to bring about such learning.
This question is incomplete, the complete question is;
Find the magnitude of the steady-state response of the system whose system model is given by
dx(t)/dt + x(t) = f(t)
where f(t) = 2cos8t. Keep 3 significant figures
Answer: The steady state output x(t) = 0.2481 cos( 8t - 45° )
Explanation:
Given that;
dx(t)/dt + x(t) = f(t) where f(t) = 2cos8t
dx(t)/dt + x(t) = f(t)
we apply Laplace transformation on both sides
SX(s) + x(s) = f(s)
(S + 1)x(s) = f(s)
f(s) / x(s) = S + 1
x(s) / f(s) = 1 / (S + 1)
Therefore
transfer function = H(s) = x(s)/f(s) = 1/(S+1)
f(t) = 2cos8t → [ 1 / ( S + 1 ) ] → x(t) = Acos(8t - ∅ )
A = Magnitude of steady state output
S = jw
S = j8
so
A = 2 × 1 / √( 8² + 1 ) = 2 / √ (64 + 1 )
A = 2/√65 = 0.2481
∅ = tan⁻¹( 1/1) = 45°
therefore The steady state output x(t) = 0.2481 cos( 8t - 45° )