Answer:
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Explanation:
sorry that i couldnt help you
Answer:
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Answer:
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
Explanation:
Sodium is present in group 1.
It is alkali metal.
It has one valence electron.
The atomic number of sodium is 11.
Its atomic mass is 23 amu.
The longhand notation of electronic configuration of sodium can be written as,
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
The electronic configuration in shorthand notation( noble gas) would be written as,
Na₁₁ = [Ne] 3s¹
Sodium loses its one valence electron to complete the octet and get stable thus form +1 cation.
It react with halogen and form salt. Such as sodium chloride.
2Na + Cl₂ → 2NaCl
The new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars. Details about pressure can be found below.
<h3>How to calculate pressure?</h3>
The pressure of a given gas can be calculated using the following formula:
P1/T1 = P2/T2
Where;
- P1 = initial pressure = 853.0 millibars
- P2 = final pressure = ?
- T1 = initial temperature = 29°C + 273 = 302K
- T2 = final temperature = 85°C + 273 = 358K
853/302 = P2/358
358 × 853 = 302P2
305374 = 302P2
P2 = 305374 ÷ 302
P2 = 1011.17 millibars
Therefore, the new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars.
Learn more about pressure at: brainly.com/question/15175692
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