The three isomers of 1,2-difluoro-1,2-dimethylcyclopentane are shown. To distinguish the three isomers we can assign the stereocenters as either R or S. Moving from left to right, the first compound has the stereocenters (1R, 2S). The compound in the middle has stereocenters (1R, 2R). The third compound on the right has stereocenters (1S, 2S). It is possible to draw what appears to be another stereoisomers with stereocenters (1S, 2R), however, this compound is a meso-compound and is identical to (1R, 2S). So there are only three unique stereoisomers of 1,2-difluoro-1,2-dimethylcyclopentane.
The answer is D. Rubber. Because A, B, and C are metal materials that will insulate heat without any gaps. Hope this helped!
Answer:
After 1326s, the concentration of pyruvic acid fall to 1/64 of its initial concentration.
Explanation:
The first order kinetics reaction is:
ln [A] = ln [A]₀ - kt
<em>Where [A] is concentration after t time, [A]₀ is intial concentration and k is reaction constant.</em>
To convert half-life to k you must use:
t(1/2) = ln 2 / K
221s = ln 2 / K
K = ln 2 / 221s
<h3>K = 3.1364x10⁻³s⁻¹</h3>
If [A] = 1/64, [A]₀ = 1:
ln [A] = ln [A]₀ - kt
ln (1/64) = ln 1 - 3.1364x10⁻³t
4.1588 = 3.1364x10⁻³s⁻¹t
1326s = t
<h3>After 1326s, the concentration of pyruvic acid fall to 1/64 of its initial concentration.</h3>
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Answer:
T2= 7.3°C
Explanation:
To solve this problem we will use Charles law equation i.e,
V1/T1 = V2/T2
Given data
V1 = 269.7 L
T1 = 6.12 °C
V2= 320.4 L
T2=?
Solution:
Now we will put the values in equation
269.7 L / 6.12°C = 320.4 L / T2
T2= 320.4 L × 6.12°C/ 269.7 L
T2= 1960.85 °C. L /269.7 L
T2= 7.3°C
Answer:
The mass chloride is 2.903 grams
Explanation:
Step1: calculate the moles of FeCl3
moles = molarity x volume in liters
volume in liters = 100 ml /1000 = 0.1 L
molarity = 0.273 M = 0.273 mol / L
moles = 0.273 mol /L x 0.1 L = 0.0273 moles
step 2: find the moles of Cl
since there is 3 atoms of cl in FeCl3
= 3 x 0.0273 =0.0819 moles
Step 3: calculate mass of cl
mass= moles x molar mass
=0.0819 moles x 35.45 g/mol = 2.903 g