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3 years ago

If a DNA molecule is found to be made of 40% thymine,What percentage guanine would you expect

1 answer:

5 0

It needs to equal the amount of adenine. The guanine to cyanine. So it would be 40% thymine 40 % adenine then 10% guanine and 10% cyanine would make sense

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Explain how the atom is electrically neutral, having an equal number of protons and electrons.

lord [1]

Answer:

A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other and atom become neutral.

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other and atom become neutral. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

For example

The carbon have six protons and six neutrons so its atomic mass is 12 amu and atomic number is six.

5 0

3 years ago

In an experiment, Lydia added 50 grams of sugar to 200 milliliters of water. She stirred the mixture, and the sugar eventually d

babymother [125]

A. physical change took place during the experiment. (plato users)

4 0

3 years ago

Read 2 more answers

Balanced equation for the combination of magnesium and oxygen to form magnesium oxide

Digiron [165]

2Mg(s) + O2(g) --> 2MgO(s)

8 0

3 years ago

The coldest temperature ever recorded on Earth was -128.6Â°F (recorded at Vostok Station, Antarctica, on July 21, 1983). Express

Sever21 [200]

Answer : The correct option is, $-89.2^oF\text{ and }183.9K$

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

$^oC=(^oF-32)\times \frac{5}{9}$

where,

$^oF$ = temperature in Fahrenheit

$^oC$ = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

$K=273.15+^oC$

where,

$K$ = temperature in Kelvin

$^oC$ = temperature in centigrade

As we are given the temperature in Fahrenheit is, -10

Now we have to determine the temperature in degree Celsius.

$^oC=(^oF-32)\times \frac{5}{9}$

$^oC=(-128.6^oF-32)\times \frac{5}{9}$

$^oC=-89.2$

Now we have to determine the temperature in Kelvin.

$K=273.15+^oC$

$K=273.15+(-89.2^oC)$

$K=183.9$

Therefore, the temperature in degree Celsius and Kelvin are, $-89.2^oF\text{ and }183.9K$

7 0

3 years ago

The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and

zavuch27 [327]

Answer:

The correct option is;

c. 0.167

Explanation:

The parameters given are;

The mean, μ = 13.9 Gigagrams/year

The standard deviation, σ = 5.8 Gigagrams/year

The z-score formula is given as follows;

$z = \dfrac{x - \mu }{\sigma }$

Where:

x = Observed score = 11.5 Gigagrams/year

We have;

$z = \dfrac{11.5 - 13.9 }{5.8 } = \dfrac{-2.4 }{5.8 } = 0.4138$

From the z-score table relations/computation, the probability (p-value) = 0.6605

Where:

x = Observed score = 14 Gigagrams/year

We have;

$z = \dfrac{14- 13.9 }{5.8 } = \dfrac{0.1}{5.8 } = 0.01724$

From the z-score table relations/computation, the probability (p-value) = 0.4931

Therefore, the probability, $p_{ca}$ , that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 15.5 Gigagrams/year and 14 Gigagrams/year = The area under the normal curve bounded by the p-values for the two amounts of carbon emission

Which gives;

$p_{ca}$ = 0.6605 - 0.4931 = 0.1674 ≈ 0.167

Therefore, the correct option is c. 0.167.

4 0

4 years ago