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Svetach [21]
3 years ago
5

Yttrium-90, Y90 , is a radioactive isotope used in the treatment of liver cancer. The half‑life of Y90 is 2.67 days. If a dose w

ith an activity of 192 μCi is given to a patient, how many days will it take for the activity of Y90 in the patient to reach 3.00 μCi?
Chemistry
1 answer:
adelina 88 [10]3 years ago
5 0

It takes 16.02 days for the activity of Y90

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles  

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

No=192 μCi

Nt=3 μCi

t1/2=2.67 days

\tt 3=192(\dfrac{1}{2})^{\dfrac{T}{2.67}}\\\\\dfrac{1}{64}=\dfrac{1}{2}^{\dfrac{T}{2.67}}\\\\\dfrac{1}{2}^6=\dfrac{1}{2}^{\dfrac{T}{2.67}}\\\\6=\dfrac{T}{2.67}\\\\T=16.02~days

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8 0
3 years ago
You can obtain a rough estimate of the size of a molecule with the following simple experiment: Let a droplet of oil spread out
mina [271]

Answer:

The diameter of the oil molecule is 4.4674\times 10^{-8} cm .

Explanation:

Mass of the oil drop = m=9.00\times 10^{-7} kg

Density of the oil drop = d=918 kg/m^3

Volume of the oil drop: v

d=\frac{m}{v}

v=\frac{m}{d}=\frac{9.00\times 10^{-7} kg}{918 kg/m^3}

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a = 4\pi r^2

a=4\times 3.14\times (0.418 m)^2=2.1945 m^2

Volume of the oil drop = v = Area × thickness

\frac{9.00\times 10^{-7} kg}{918 kg/m^3}=2.1945 m^2\times x

x= 4.4674\times 10^{-10} m= 4.4674\times 10^{-8} cm

The thickness of the oil drop is 4.4674\times 10^{-8} cm and so is the diameter of the molecule.

6 0
2 years ago
18 the first step in the mechanism is the acid catalyzed generation of an enol and then electrophilic addition of bromine. which
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the first step in the mechanism is the acid-catalyzed generation of an enol and then electrophilic addition of bromine and cation is formed because of the destabilization effect of the electronegativity of oxygen

The ability of an atom or functional group to draw electrons to itself is known as an electronegativity in chemistry. An atom's electronegativity is influenced by both its atomic number and how far away from its charged nuclei its valence electrons are located.

The ability of an atom to draw shared electrons in a covalent connection is referred to as electronegativity. The stronger an element attracts the shared electrons, the higher its degree of electronegativity.

The propensity of an atom to attract other atoms when it is combined is known as an element's electronegativity. Additionally, a pair of bound electrons are shared. In contrast, an element's electropositivity refers to an atom's propensity to contribute electrons while also withdrawing from covalent connections.

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5 0
2 years ago
Nuclear energy is released during:
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B, C and E. In radioactive decay unstable atoms stabilize by releasing energy.
3 0
3 years ago
Read 2 more answers
Use the periodic table and example bond table to answer the question.
lyudmila [28]

In keeping with the general trends, K-Br will have the smallest bond energy. The bond energy refers to the energy that keeps the atoms in a bond together.

<h3>What is bond energy?</h3>

Bond energy is the energy that is required to hold atoms together in a bond. This energy must also be supplied when the atoms are to be separated.

We have the bond energies of each of the bons in the question, we have to note that the the smallest value of bond energy is Na-Br hence in keeping with the general trends, K-Br will have the smallest bond energy.

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