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3 years ago

What needs to happen for a solute to dissolve in a particular solvent

1 answer:

7 0

<span>the atractions between the solute and solvent molecules must be greater than the atractions keeping the solute together and the atractions keeping the solvent togetherrr.</span>

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The equilibrium constant, K., for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC13(E) Calculate the equilibrium

lord [1]

Answer:

The equilibrium concentration of $PCl_5=0.228 M$ .

The equilibrium concentration of $PCl_3=0.280 M -0.228 M=0.052M$ .

The equilibrium concentration of $Cl_2=0.280 M -0.228 M=0.052M$ .

Explanation:

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = $K_c=83.3$

Moles of $PCl_3 = 0.280 mol$

Concentration of $[PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M$

Moles of $Cl_ = 0.280 mol$

Concentration of $[Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M$

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

Initial: 0.280 0.280 0

At eq'm: (0.280-x) (0.280-x) x

We are given:

$[PCl_3]_{eq}=(0.280-x)$

$[Cl_2]_{eq}=(0.280-x)$

$[PCl_5]_{eq}=x$

Calculating for 'x'. we get:

The expression of $K_{c}$ for above reaction follows:

$K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}$

Putting values in above equation, we get:

$83.3=\frac{x}{(0.280-x)\times (0.280-x)}$

On solving this quadratic equation we get:

x = 0.228, 0.344

0.228 M < 0.280 M< 0.344 M

x = 0.228 M

The equilibrium concentration of $PCl_5=0.228 M$ .

The equilibrium concentration of $PCl_3=0.280 M -0.228 M=0.052M$ .

The equilibrium concentration of $Cl_2=0.280 M -0.228 M=0.052M$ .

4 0

3 years ago

A chemist found a 60.00 gram sample containing copper and oxygen. Given the following percent composition, what is the mass of c

Strike441 [17]

The answer should 34.25g of Cu.

6 0

3 years ago

Which which type of weather technology often carries cameras that can make images of Earth's surface, clouds, and snow cover?

Ludmilka [50]

B:weather satellite.

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3 years ago

Read 2 more answers

How do you use the changes in the phase of water to keep you cool?

sineoko [7]

Answer:

by freezing

Explanation:

8 0

3 years ago

The amount of heat absorbed by the alcohol was determined to be 1.17kJ. Given that the specific heat of the alcohol is 2.42J/gC

quester [9]

Answer:

ΔT = 20.06 °C

Explanation:

The equation used for this problem is as follow,

Q = m Cp ΔT ----- (1)

Where;

Q = Heat = 1.17 kJ = 1170 J

m = mass = 24.1 g

Cp = Specific Heat Capacity = 2.42 J.g⁻¹.°C⁻¹

ΔT = Change in Temperature = <u>??</u>

Solving eq. 1 for ΔT,

ΔT = Q / m Cp

Putting values,

ΔT = 1170 J / 24.1 g × 2.42 J.g⁻¹.°C⁻¹

ΔT = 20.06 °C

6 0

3 years ago