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Elina [12.6K]
2 years ago
6

which of the following requires the most energy to break a bond? a. breaking cl-br bond. b. breaking a n-p bond. c. breaking a o

-o bond. d. none of the above.
Chemistry
1 answer:
irina1246 [14]2 years ago
6 0

A. Breaking a Cl-Br bond

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An atomic radius is about 1.00*10^2 pm. Convert the radius to inches. (1 pm=10^-12m)
natka813 [3]

Answer:

3.937 x 10⁻⁸ inches

Explanation:

Data Given:

Atomic radium in pm (picometer) = 1.00 x 10² pm

Atomic radium in inches = ?

1 pm = 10⁻¹² m

Solution:

First convert picometer to meter

As we Know

  1 pm = 10⁻¹² m

then

  1.00 x 10² pm = X meter

Do cross multiplication

        X meter = (1.00 x 10² pm)(10⁻¹² m) / 1 pm

       X meter = 1 x 10⁻⁹ m

So, 1.00 x 10² pm equal to 1 x 10⁻⁹ m

Now convert meter to inches

As

         1 m = 39.37 inches

         1 x 10⁻⁹ m = X inches

Do cross multiplication

        X inches = (39.3701 inches)(1 x 10⁻⁹ m ) / 1 m

        X inches = 3.937 x 10⁻⁸ inches

So,

1.00 x 10² pm = 3.937 x 10⁻⁸ inches

so the radius is 3.937 x 10⁻⁸ inches

4 0
2 years ago
Which molecule is an alkene?
belka [17]
D is an alkene because the ending is cis-2-pentene if it was an alkane is would be pentane.
4 0
2 years ago
N-hexane boils at 68.7 oC at 1.013 bar and the heat of Vaporization is 28850
miss Akunina [59]
He one 28850




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8 0
3 years ago
14) The central iodine atom in the ICl4- ion has __________ nonbonded electron pairs and __________ bonded electron pairs in its
masha68 [24]

Answer:

Two non bonded electron pairs and four bonded electron pairs

Explanation:

An image of the compound as obtained from chemlibretext is attached to this answer.

The ion ICl4- ion, is an AX4E2 ion. This implies that there are four bond pairs and two lone pairs of electrons. As expected, the shape of the ion is square planar since the lone pairs are found above and below the plane of the square. This is clear from the image attached.

7 0
2 years ago
Which trends appear as the elements in Period 3 are considered from left to right?
andreev551 [17]

Answer:

Metallic character decreases, and electronegativity increases.

Explanation:

Hello!

In this case, according to the organization of the periodic table, we can see that from left to right, the electronegativity increases as nonmetals are able to attract electrons more easily than metals.

Moreover, in contrast to the previous periodic trend, the metallic character decreases from left to right because the elements tend to decrease the capacity to lose electrons and consequently start attracting them.

Thus, the answer would be: "Metallic character decreases, and electronegativity increases".

Best regards!

8 0
3 years ago
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