The acceleration due to gravity on earth is 9.8 m/s2. what is the weight of a 75 kg person on earth

jekas [21]

C.) cool feet walking across a hot pavement.

The reason because the other ones deals with radiation. Only C.) is the right answer because the feet is touching the hot pavement which is conduction.

3 0

2 years ago

I am a give awayer please like this and say thanks

s344n2d4d5 [400]

Answer:

what.....................

i edited this answer

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4 0

2 years ago

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A point charge of 5.0 x 10^-7 C moves to the right at 2.6 x 10^5 m/s in a magnetic field that is directed into the screen and ha

-BARSIC- [3]

The magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

<h3>What is magnetic force?</h3>

A magnetic force is the force that act in a magnetic field.

To calculate the magnetic force, we use the formula below.

Formula:

F = qvB.........Equation 1

Where:

F = magnetic force
q = point charge
v = Velocity of the the charge
B = Field strength

From the question,

Given:

q = 5.0×10⁻⁷ C
v = 2.6×10⁵ m/s
B = 1.8×10⁻² T

Substitute these values into equation 2

F = (5.0×10⁻⁷)(2.6×10⁵)(1.8×10⁻²)
F = 23.4×10⁻⁴
F = 2.34×10⁻³ N

Hence, the magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

Learn more about magnetic force here: brainly.com/question/2279150

#SPJ12

5 0

1 year ago

Lagrangian mechanics. Determine the equations of motion for a particle of mass m constrained to move on the surface of a cone in

maria [59]

Answer:

Explanation:

Hi!

In order to obtain the Lagrangian of the system we must first write the Kinetic and Potential Energies. Lets orient our axes such that the axis of the cone coincide with the z axis. In cilindrical coordinates we have

$v^{2} = \frac{dr}{dt}^{2} +r^{2} \frac{d\theta }{dt} ^{2} +\frac{dz}{dt} ^{2}$ - (1)

But, since the particle is constrained to move on the surface of the cilinder, we have the following relation between r and z:

$\frac{r}{z}=tan(45)$

or:

$z = r cot(45)$ - (2)

and:

$\frac{dz}{dt} = \frac{dr}{dt} cot(45)$

replacing (2) in (1) we obtain:

$v^{2} = \frac{dr}{dt}^{2} (1+cot(45))+r^{2}\frac{d\theta }{dt} ^{2}$ - (3)

Now the kinetic energy is given as:

$T = \frac{1}{2}m(\frac{dr}{dt}^{2} (1+cot(45))+r^{2}\frac{d\theta }{dt} ^{2})$ - (4)

And the potential energy is given by:

$V = -mgz = -mgr cot(45)$

So the Langrangian is given by:

$L = T - V= \frac{1}{2}m(\frac{dr}{dt}^{2}(1+cot(45)+r^{2})\frac{d\theta }{dt} ^{2}) + mgr cot(45)$

And the equations of motion are:

For θ

$\frac{d}{dt} (mr\frac{d\theta}{dt}) = 0-->mr{d\theta}{dt}=c$

For r

$\frac{d}{dt}(m\frac{dr}{dt}(1+cot(45) )= mgcot(45)+mr\frac{d\theta}{dt} ^{2}\\m\frac{d^{2} r}{dt^{2} }(1+cot(45)= mgcot(45)+mr\frac{d\theta}{dt} ^{2}$

Obtained from the Euler-Langrange equations

Here the conserved quantity is given by the first equation of motion, namely:

$mr\frac{d\theta}{dt}=c$

Which is the magnitude of the angular momentum

7 0

2 years ago

Julian tests four springs and records the results in the table

Tju [1.3M]

Answer:

list of spring in order of increasing spring constant is given by,

W, Y, X, Z

Explanation:

Spring W:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 20 / 0.5

k = 40 N/m

Spring X:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 60 / 0.3

k = 200 N/m

Spring Y:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 40 / 0.4

k = 100 N/m

Spring Z:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 50 / 0.1

k = 500 N/m

Thus, list of spring in order of increasing spring constant is given by,

W, Y, X, Z

8 0

2 years ago

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