Answer:
47 m/s
Explanation:
golf club mass, mc = 180 g
golf ball mass, mb = 46 g
initial golf club speed, vc1 = 47 m/s
final golf club speed, vc2 = 35 m/s
initial golf ball speed, vb1 = 0 m/s
final golf ball speed, vb2 = ? m/s
The total momentum is conserved, then:
mc*vc1 + mb*vb1 = mc*vc2 + mb*vb2
Replacing with data and solving (dimension are omitted):
180*47 + 46*0 = 180*35 + 46*vb2
vb2 = (180*47 - 180*35)/46
vb2 = 47 m/s
Answer:
2406 miles
Explanation:
Let A be the starting position, B the junction position and C the final position after flying the 3.5 hrs. Also, let b be the distance from the starting point:

#Distance traveled in 1.5hrs is;

#Distance traveled in next two hrs:

#Now using the Cosine Rule:

Hence, the pilot is 2406 miles from her starting position.
Answer:
58.8 N
Explanation:
The normal force is calculated as equal to the perpendicular component of the gravitational force.
Thus; N = mg
We are given m = 6 kg
Thus;
N = 6 × 9.8
N = 58.8 N
Thus, magnitude of normal force on the rock = 58.8 N
Answer:
D I think I might be wrong its been a while scense I did something like that
Answer:
i. The radius 'r' of the electron's path is 4.23 ×
m.
ii. The frequency 'f' of the motion is 455.44 KHz.
Explanation:
The radius 'r' of the electron's path is called a gyroradius. Gyroradius is the radius of the circular motion of a charged particle in the presence of a uniform magnetic field.
r = 
Where: B is the strength magnetic field, q is the charge, v is its velocity and m is the mass of the particle.
From the question, B = 1.63 ×
T, v = 121 m/s, Θ =
(since it enters perpendicularly to the field), q = e = 1.6 ×
C and m = 9.11 ×
Kg.
Thus,
r =
÷ sinΘ
But, sinΘ = sin
= 1.
So that;
r = 
= (9.11 ×
× 121) ÷ (1.6 ×
× 1.63 ×
)
= 1.10231 ×
÷ 2.608 × 
= 4.2266 ×
= 4.23 ×
m
The radius 'r' of the electron's path is 4.23 ×
m.
B. The frequency 'f' of the motion is called cyclotron frequency;
f = 
= (1.6 ×
× 1.63 ×
) ÷ (2 ×
× 9.11 ×
)
= 2.608 ×
÷ 5.7263 × 
= 455442.4323
f = 455.44 KHz
The frequency 'f' of the motion is 455.44 KHz.