Answer:
Explanation:
Given a square side loop of length 10cm
L=10cm=0.1m
Then, Area=L²
Area=0.1²
Area=0.01m²
Given that, frequency=60Hz
And magnetic field B=0.8T
a. Flux Φ
Flux is given as
Φ=BA Sin(wt)
w=2πf
Φ=BA Sin(2πft)
Φ=0.8×0.01 Sin(2×π×60t)
Φ=0.008Sin(120πt) Weber
b. EMF in loop
Emf is given as
EMF= -N dΦ/dt
Where N is number of turns
Φ=0.008Sin(120πt)
dΦ/dt= 0.008×120Cos(120πt)
dΦ/dt= 0.96Cos(120πt)
Emf=-NdΦ/dt
Emf=-0.96NCos(120πt). Volts
c. Current induced for a resistance of 1ohms
From ohms law, V=iR
Therefore, Emf=iR
i=EMF/R
i=-0.96NCos(120πt) / 1
i=-0.96NCos(120πt) Ampere
d. Power delivered to the loop
Power is given as
P=IV
P=-0.96NCos(120πt)•-0.96NCos(120πt)
P=0.92N²Cos²(120πt) Watt
e. Torque
Torque is given as
τ=iL²B
τ=-0.96NCos(120πt)•0.1²×0.8
τ=-0.00768NCos(120πt) Nm
Answer:
Bottom left corner for whatever group that is
Lithium, sodium, and potassium all react with water
Answer:
6.02 radian
Explanation:
At 12 noon position is zero radian on Monday
at 12 midnight the position is π/2
at 11 am position on Tuesday is 2π/24 x 23 ( after 23 hours ) = 6..02 radian.
950kg. It is W=mg. therefore, mass= W/g which is W/10
=9500/10
=950
Answer: High voltage transmission minimizes energy losses during electricity transmission.
Explanation:
When electricity is to be transmitted over a long distance, high voltage transmission is preferred to minimize energy losses due to heat.
The higher the transmission voltage, the lower the current and the lesser the resitance in the wire and the lesser the energy lost due to heat during transmission.
High voltage transmission in kilowatts enables light weight cables to be used for long distance electricity transmission.
This explains why, even though only 110 V may be required at home by some appliances, but electricity is transmitted in kilovolts and often require a stepdown transformer
