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Lyrx [107]
3 years ago
10

You have a 1.7 μf and a 2.2 μf capacitor. what values of capacitance could you get by connecting them in parallel?

Physics
2 answers:
Rus_ich [418]3 years ago
5 0
You have to add 1.7 and 2.2 together!
1.7+2.2=3.9μF
Dominik [7]3 years ago
5 0
The effective capacitance of capacitors in parallel is
the sum of the individual capacitances.

The only value of capacitance you could get with
those two in parallel is

                               (1.7 uF + 2.2 uF) = 3.9 uF
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A powerful motorcycle can produce an acceleration of 3.00 m/s2 while traveling at 90.0 km/h. At that speed the forces resisting
nata0808 [166]

Answer:

1185 N

Explanation:

From Newton’s second law of motion,  

F=ma where m= mass of motorcycle, a is acceleration of the motorcycle and F=Force

Net force acting on motorcycle F_{net} is given by  F_{net}=F-f

Where F is force acting on motorcycle and f is frictional force

Substituting F-f for F_{net}

F_{net}=ma hence  ma= F- f Substituting a with 3, m with 245Kg and f with 450N as provided

245*3= F- 450

F=245*3 +450= 1185 N

6 0
3 years ago
Which type of electricity is a one-time event, caused by unbalanced charges trying to become neutral again?
arlik [135]

Answer: yes

Explanation:

7 0
3 years ago
A 1200-kg car accelerates it’s speed from 4 m/s to 10 m/s in 3 seconds. Find the car average speed , the car acceleration , the
dsp73

Answer:

Given: mass 1200kg

initial velocity: 4m/s

finial velocity: 10 m/s

time 3 sec

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4+10/3

: 4.66m/s2

8 0
3 years ago
In the heat equation, what does c represent
Bingel [31]
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Hope this helps!
5 0
3 years ago
Read 2 more answers
A steady electric current flows through a wire. If 9.0 C of charge passes a particular spot in the wire in a time period of 2.0
defon

1) Current: 4.5 A

2) Time taken: 4.7 s

Explanation:

1)

The electric current intensity is defined as the rate at which charge flows in a conductor; mathematically:

I=\frac{q}{t}

where

I is the current

q is the amount of charge passing a given point in a time t

For the wire in this problem, we have

q = 9.0 C is the amount of charge

t = 2.0 s is the time interval

Solving for I, we find the current:

I=\frac{9.0}{2.0}=4.5 A

2)

To solve this problem, we can use again the same formula

I=\frac{q}{t}

where

I is the current

q is the amount of charge passing a given point in a time t

In this problem, we have:

I = 3.0 A (current)

q = 14.0 C (charge)

Therefore, the time taken for the charge to move past a particular spot in the wire is

t=\frac{q}{I}=\frac{14.0}{3.0}=4.7 s

Learn more about electric current:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

8 0
3 years ago
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