You have a 1.7 μf and a 2.2 μf capacitor. what values of capacitance could you get by connecting them in parallel?
2 answers:
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Answer:
The magnitude of electric field is 22.58 N/C
Solution:
Given:
Force exerted in upward direction,
Charge, Q =
Now, we know by Coulomb's law,
Also,
Electric field,
Thus from these two relations, we can deduce:
F = QE
Therefore, in the question:
Here, the negative side is indicative of the Electric field acting in the opposite direction, i.e., downward direction.
The magnitude of the electric field is:
Answer:
Q/4πε0 [1/R - 1/√R2+d2]
Explanation:
Q/4πε0 [1/R - 1/√R2+d2] is the answer
explanation is attached.
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