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jeka94
3 years ago
5

Kinetic energy....

Physics
1 answer:
Solnce55 [7]3 years ago
7 0

Explanation:

Given parameters:

mass of bullet 1 = 0.0014kg

velocity of bullet 1 = 396m/s

mass of bullet 2 = 7.1 x 10⁷kg

velocity of bullet 2 = 13m/s

Unknown;

Comparing the kinetic energy

Solution:

Kinetic energy is the energy due to the motion of a body.

   K.E = \frac{1}{2} m v^{2}

bullet 1:

  K.E =  \frac{1}{2} x 0.0014 x  396^{2} = 109.8J

bullet 2:

 K.E =  \frac{1}{2} 7.1 x 10⁷ x  13^{2} = 6 x 10⁹J

The second bullet has more kinetic energy than the first one.

Learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

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Answer:

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Keeping the mass at 1.0 kg and the velocity at 10.0 m/s, record the magnitude of centripetal acceleration for each given radius
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Answer:

The centripetal acceleration for the first radius; 2.0 m = 50 m/s²

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The centripetal acceleration for the fourth radius; 8.0 m = 12.5 m/s²

The centripetal acceleration for the fifth radius; 10.0 m = 10 m/s²

Explanation:

Given;

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different values of the radius, 2.0 m 4.0 m 6.0 m 8.0 m 10.0 m

The centripetal acceleration for the first radius; 2.0 m

a_c = \frac{v^2}{r} \\\\a_c_1= \frac{(10)^2}{2} \\\\a_c_1= 50 \ m/s^2

The centripetal acceleration for the second radius; 4.0 m

a_c_2= \frac{(10)^2}{4} \\\\a_c_2= 25 \ m/s^2

The centripetal acceleration for the third radius; 6.0 m

a_c_3= \frac{(10)^2}{6} \\\\a_c_3= 16.67 \ m/s^2

The centripetal acceleration for the fourth radius; 8.0 m

a_c_4= \frac{(10)^2}{8} \\\\a_c_4= 12.5 \ m/s^2

The centripetal acceleration for the fifth radius; 10.0 m

a_c_5= \frac{(10)^2}{10} \\\\a_c_5= 10 \ m/s^2

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\neq v=\frac{distance}{time} \\18\,\frac{m}{s}  = \frac{distance}{240\,\,s} \\distance=18\,*\,240\,\,m\\distance= 4320\,\,m

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