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Vladimir [108]
3 years ago
9

HELP PLEASE ASAP

Physics
1 answer:
dusya [7]3 years ago
5 0

Answer: (displacement/delta x) = -50. m, and distance dropped = 50. m (50. m below the starting location)

Explanation:

We know that the initial velocity of the tuna can is 0 m/s, as it is at rest. Also, we have the acceleration caused by gravity (-9.8 m/s^2). The time for the trip is 3.2 s. We need to find the displacement, or delta x.

To do this, we need to use a freefall equation. The one we can use with initial velocity, time, and acceleration would be the following:

d = (initial velocity)(time) + (1/2)(acceleration caused by gravity)(time)^2

d = (vi)(t) + 1/2(g)(t)^2

d = (0 m/s)(3.2 s) + 1/2(-9.8 m/s^2)(3.2 s)^2

d = 1/2(-9.8 m/s^2)(3.2 s)^2

d = -4.9(3.2)^2

d = -4.9(10.24)

d = -50.176 = <u><em>-50. m</em></u>

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A boy whirls a ball on a string in a horizontal circle of radius 0.65 m. If the ball is traveling at 9 m/s, what is the centripe
djverab [1.8K]

Answer:

ac = 124.6 m/s²

Explanation:

When an object executes a uniform circular motion, acceleration is produced in it due to a change in its direction during the motion. This acceleration is called the centripetal acceleration. The formula used to find this acceleration is given as follows:

a_{c} = \frac{v^{2}}{r}\\

where,

ac = centripetal acceleration = ?

v = speed = 9 m/s

r = radius = 0.65 m

Therefore,

a_{c} = \frac{(9\ m/s)^{2}}{0.65\ m}\\

<u>ac = 124.6 m/s²</u>

5 0
3 years ago
An object experiences an acceleration of -6.8 m/s​2.​ As a result, it accelerates from 54 m/s to a complete stop. How much dista
inessss [21]

Answer:

The distance traveled during its acceleration, d = 214.38 m

Explanation:

Given,

The object's acceleration, a = -6.8 m/s²

The initial speed of the object, u = 54 m/s

The final speed of the object, v = 0

The acceleration of the object is given by the formula,

                                      a = (v - u) / t   m/s²

       ∴                              t = (v - u) / a

                                         = (0 - 54) / (-6.8)

                                         = 7.94 s

The average velocity of the object,

                                       V = (54 + 0)/2

                                           = 27 m/s

The displacement of the object,

                                 d = V x t   meter

                                    = 27 x 7.94

                                    = 214.38 m

Hence, the distance the object traveled during that acceleration is, a = 214.38 m

3 0
3 years ago
What is the normal force and gravitational force on a 55 kg person standing stationary?
Alex777 [14]

Answer:

539.55 N for both

Explanation:

F=ma

Mass is given at 55kg

And when finding gravitational force gravity's constant is an acceleration of 9.81m/s

F=(55)(9.81)

F= 539.55 N (for both)

Normal force cancels out gravitational force that's why we don't fall throught the floor.

We push down on the floor due to gravitational force but normal force keeps us upright pushing an equal amount back.

4 0
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