A series circuit has only one path for current,
while a parallel circuit has more than one.
![\qquad\qquad\huge\underline{{\sf Answer}}♨](https://tex.z-dn.net/?f=%5Cqquad%5Cqquad%5Chuge%5Cunderline%7B%7B%5Csf%20Answer%7D%7D%E2%99%A8)
Gravitational Potential of an object with mass m, and height of h metre is :
![\qquad \sf \dashrightarrow \:mgh](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3Amgh)
Now, if the mass of object is 2100 kg, height of 18 m is placed in there, then it's gravitational potential energy is ~
![\qquad \sf \dashrightarrow \:2100 \times 10 \times 18](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A2100%20%5Ctimes%2010%20%5Ctimes%2018)
![\qquad \sf \dashrightarrow \:378000 \: \: joules](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A378000%20%5C%3A%20%20%5C%3A%20joules)
![\qquad \sf \dashrightarrow \:3.78 \times 10 {}^{5} \: \: joules](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A3.78%20%5Ctimes%2010%20%7B%7D%5E%7B5%7D%20%20%5C%3A%20%20%5C%3A%20joules)
<em>math</em><em>ematically</em><em>,</em>
<em>
</em>
<em>where</em><em> </em><em>t</em><em> </em><em>=</em><em> </em><em>tim</em><em>e</em>
<em>from</em><em> </em><em>the</em><em> </em><em>q</em><em>uestion</em><em>,</em><em> </em><em>t</em><em>=</em><em> </em><em>0</em><em>.</em><em>0</em><em>7</em><em>7</em><em>s</em><em>e</em><em>c</em>
<em>sub</em><em>stitute</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>th</em><em>e</em><em> formula</em>
<em>
</em>
<em>
</em>
<em>approximately</em><em> </em><em>1</em><em>3</em><em>s</em><em>^</em><em>-</em><em>1</em>
It's important because you have to know when to make it go faster or else you might not be able to go upside down or in a circle
Answer:
vf=94.4 m/s
Explanation:
acceleration is the final velocity minus initial velocity divided by time
a = (vf-vi)/t
Given:
a= 14.2 m/s^2
vi= 0 (at rest)
t = 6.6
Solve for vf
a = (vf-vi)/t
a*t=vf-vi
(14.2)*(6.6)=vf - 0
vf=94.4 m/s