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Ierofanga [76]
4 years ago
6

What is the largest tsunami ever recorded

Physics
1 answer:
Vlada [557]4 years ago
8 0
<h2>Answer: The tsunami occurred on 1958 at Lituya Bay, Alaska. </h2>

The Lituya Bay tsunami occurred on July 9th, 1958, northeast of the Gulf of Alaska. It was as a consequence of a strong earthquake of magnitude 8.3 on the Ritchter scale along the Fairweather Fault in the Alaskan Panhandle, which caused a landslide in a fjord in Lituya Bay, collapsing an entire mountain and generating a gigantic wave that rose to <u>524 meters</u>, the highest recorded so far.

It should be noted that despite its great magnitude and having uprooted all the trees and vegetation of the place, this mega-tsunami claimed only five lives because the area was not as inhabited as the large cities are.

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A person throws a ball with a force of 140 N that accelerates at 15 m/s? What is the mass of the
mr_godi [17]

Newton's 2nd law

\tt \sum F=m.a

input the value:

\tt m=\dfrac{\Sum F}{a}=\dfrac{140~N}{15~m/s^2}=9.3~kg

6 0
3 years ago
Write a difference between force and work? ​
Nesterboy [21]

Answer:

force is a derived quantity

work is a fundamental quantity

2.Force is measured in Newton why work is measured in Newton per seconds (N/s)

Explanation:

no

3 0
3 years ago
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The speed of light in a vacuum is 2.998Ã108 m/s. calculate its speed in miles per hour (miles/h).
snow_tiger [21]
670616629.3844 miles per hour
7 0
3 years ago
How are frequency and wave period Related?
exis [7]

The frequency and period of any wave are reciprocals.

Frequency = 1/period and Period = 1/frequency .

That means that the product of (frequency) times (period) of any wave is always the same. The product is always ' 1 ', with no unit.

7 0
3 years ago
If a CFOC was launched and travels 65 meters and is in the air for 3 seconds, what is the launch velocity and angle?
labwork [276]

Answer:

Lauch velocity (u) = 26.15 m/s

Lauch Angle (θ) = 35°

Explanation:

From the question given above, the following data were obtained:

Range (R) = 65 m

Time of flight (T) = 3 s

Acceleration due to gravity (g) = 10 m/s²

Lauch velocity (u) =?

Lauch Angle (θ) =?

R = u²Sin2θ /g

65 = u² × Sin2θ /10

Recall:

Sin2θ = 2SinθCosθ

65 = u² × 2SinθCosθ / 10

65 = u² × SinθCosθ / 5

Cross multiply

65 × 5 = u² × SinθCosθ

325 = u² × SinθCosθ .....(1)

T = 2uSinθ / g

3 = 2uSinθ / 10

3 = uSinθ / 5

Cross multiply

3 × 5 = uSinθ

15 = u × Sinθ

Divide both side by Sinθ

u = 15 / Sinθ....... (2)

Substitute the value of u in equation (2) into equation (1)

325 = u² × SinθCosθ

u = 15 / Sinθ

325 = (15 / Sinθ)² × SinθCosθ

325 = 225 / Sin²θ × SinθCosθ

325 = 225 × SinθCosθ / Sin²θ

325 = 225 × Cosθ / Sinθ

Cross multiply

325 × Sineθ = 225 × Cosθ

Divide both side by Cosθ

325 × Sineθ / Cosθ = 225

Divide both side by 325

Sineθ / Cosθ = 225 / 325

Sineθ / Cosθ = 0.6923

Recall:

Sineθ / Cosθ = Tanθ

Tanθ = 0.6923

Take the inverse of Tan

θ = Tan¯¹ 0.6923

θ = 35°

Substitute the value of θ into equation (2) to obtain the value of u.

u = 15 / Sinθ

θ = 35°

u = 15 / Sin 35

u = 15 / 0.5736

u = 26.15 m/s

Summary:

Lauch velocity (u) = 26.15 m/s

Lauch Angle (θ) = 35°

8 0
3 years ago
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