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Ierofanga [76]
3 years ago
6

What is the largest tsunami ever recorded

Physics
1 answer:
Vlada [557]3 years ago
8 0
<h2>Answer: The tsunami occurred on 1958 at Lituya Bay, Alaska. </h2>

The Lituya Bay tsunami occurred on July 9th, 1958, northeast of the Gulf of Alaska. It was as a consequence of a strong earthquake of magnitude 8.3 on the Ritchter scale along the Fairweather Fault in the Alaskan Panhandle, which caused a landslide in a fjord in Lituya Bay, collapsing an entire mountain and generating a gigantic wave that rose to <u>524 meters</u>, the highest recorded so far.

It should be noted that despite its great magnitude and having uprooted all the trees and vegetation of the place, this mega-tsunami claimed only five lives because the area was not as inhabited as the large cities are.

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A student wearing frictionless in-line skates on a horizontal surface is pushed, starting from rest, by a friend with a constant
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Answer:

Physics

Explanation:

Explanation:

We can use the Theorem of Work (W) and Kinetic Energy (K):

W=ΔK=Kf−Ki

it basically tells us that the work done on our system will show up as change in Kinetic Energy:

We know that the initial Kinetic Energy, Ki=12mv2i, is zero (starting from rest) while the final will be equal to 352J; Work will be force time displacement. so we get:

F⋅d=Ff

45d=352

and so:

d=35245=7.8≈8m

8 0
3 years ago
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How long does it take a vehicle to reach a velocity of 32 m/s if it accelerates from rest at a rate of 4.2 m/s^2?
Marta_Voda [28]

Answer:

7.62

Explanation:

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4 0
3 years ago
Compressing the air by squeezing the bottle was accompanied by a(n) ________ in the temperature of air inside the bottle
Georgia [21]
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3 0
3 years ago
You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a
zepelin [54]

Answer:

You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.

Explanation:

Given Values:

L = 50 cm = 0.5 m

H = 170 j/s

To find the diameter of the rod, we have to find the area of the rod using the following formula.

Here Tc = 100.0° C

        k  = 50.2

       H = k × A × \frac{[T_{H -}T_{C} ] }{L}

Solving for A

       A  =  \frac{H * L }{k * [ T_{H}- T_{C} ] }

       A  = \frac{170 * 0.5}{50.2 * [ 350 - 100 ]}

       A  = \frac{85}{12550} = 6.77 ×10^{-3} m²

Now Area of cylinder is :

     A =  \frac{\pi }{4} d²

solving for d:

    d =  \sqrt{\frac{4 * 0.00677 }{\pi } }

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5 0
4 years ago
Which one of the following distances is the shortest?
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