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grandymaker [24]
3 years ago
13

If 143 joules of work are needed to move a box 9 meters, what force was used?

Physics
2 answers:
zhuklara [117]3 years ago
8 0

Answer: 16 N

Explanation: Work is expressed in this formula:

W=F x d

Derive for F:

F= W /d

= 143 J / 9 m

= 16 N

brilliants [131]3 years ago
7 0
Your gonna have to divide 143 into 9 and then that will be your answer
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Choose the correct definitions of speed, velocity, and acceleration. Check all that apply. Acceleration tells us in which direct
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We have thatThe options that define Speed, Velocity,Acceleration.

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B,D,E

From the question we are told

Choose the correct definitions of speed, velocity, and acceleration. Check all that apply.

  • Acceleration tells us in which direction the object is going. Speed is the rate of change of velocity in time.
  • Acceleration is the rate of change of velocity in time.
  • Velocity is used to describe changes in the movement direction of the object. Acceleration tells us how far the object will go in a certain amount of time.
  • Velocity is used to describe how fast the object is moving and tells us in which direction it is going.
  • Speed is used to describe how fast the object is moving.
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Speed is used to describe how fast the object is moving and tells us in which direction it is going.

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For more information on this visit

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3 0
2 years ago
Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.
o-na [289]

Answer:

Current = 10 Amperes.

Explanation:

Given the following dat;

Quantity of charge, Q = 36 kilocoulombs (KC) = 36 * 1000 = 36000C

Time = 1 hour to seconds = 60*60 = 3600 seconds

To find the current;

Quantity of charge = current * time

Substituting in the equation

36000 = current * 3600

Current = 36000/3600

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6 0
3 years ago
Air as an ideal gas enters a diffuser operating at steady state at 5 bar, 280 K with a velocity of 510 m/s. The exit velocity is
Nataly [62]

Answer:

Explanation:

Calculating the exit temperature for K = 1.4

The value of c_p is determined via the expression:

c_p = \frac{KR}{K_1}

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R = universal gas constant = \frac{8.314 \ J}{28.97 \ kg.K}

k = constant = 1.4

c_p = \frac{1.4(\frac{8.314}{28.97} )}{1.4 -1}

c_p= 1.004 \ kJ/kg.K

The derived expression from mass and energy rate balances reduce for the isothermal process of ideal gas is :

0=(h_1-h_2)+\frac{(v_1^2-v_2^2)}{2}     ------ equation(1)

we can rewrite the above equation as :

0 = c_p(T_1-T_2)+ \frac{(v_1^2-v_2^2)}{2}

T_2 =T_1+ \frac{(v_1^2-v_2^2)}{2 c_p}

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T_2= 280+\frac{((510)^2-(120)^2)}{2(1.004)} *\frac{1}{10^3}

T_2 = 402.36 \ K

Thus, the exit temperature = 402.36 K

The exit pressure is determined by using the relation:\frac{T_2}{T_1} = (\frac{P_2}{P_1})^\frac{k}{k-1}

P_2=P_1(\frac{T_2}{T_1})^\frac{k}{k-1}

P_2 = 5 (\frac{402.36}{280} )^\frac{1.4}{1.4-1}

P_2 = 17.79 \ bar

Therefore, the exit pressure is 17.79 bar

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Answer:

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