With what tension must a rope with length 2.20 m and mass 0.150 kg be stretched for transverse waves of frequency 43.0 hz to hav
1 answer:
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Answer:
find the diagram in the attachment.
Explanation:
Let vi = 12 m/s be the intial velocy when the ball is thrown, Δy be the displacement of the ball to a point where it starts returning down, g = 9.8 m/s^2 be the balls acceleration due to gravity.
considering the motion when the ball thrown straight up, we know that the ball will come to a stop and return downwards, so:
(vf)^2 = (vi)^2 + 2×g×Δy
vf = 0 m/s, at the highest point in the upward motion, then:
0 = (vi)^2 + 2×g×Δy
-(vi)^2 = 2×g×Δy
Δy = [-(vi)^2]/2×g
Δy = [-(-12)^2]/(2×9.8)
Δy = - 7.35 m
then from the highest point in the straight up motion, the ball will go back down and attain the speed of 12 m/s at the same level as it was first thrown
Answer:
20.45%
Explanation:
The probability that the student got a B is
Now, how many students are there in total?
The answer is
How many students got a B?
The answer is
therefore, the probability that the student has got a B is
Hence, the probability that a student has got a B is 20.45%