1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leonid [27]
3 years ago
9

What is the probability that the value the standard normal random variable assumes will be greater than 0.64?

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0
For the answer to the question above, I'll provide a computation on my answer to give clarity and understanding to my answer.
<span>P(z> 0.64) = 1- P(z<0.64) </span>
<span>P(z<0.64) = .73891 </span>
<span>P(z> 0.64) = 1- 0.73891 =
So the answer to your question is
0.26109 

I hope my answer helped you. Have a nice day!</span>
You might be interested in
Problem 6? Helpppp pleaseeeee
Pachacha [2.7K]
D.36 60 .... because 6 times 6 is 36 and 6 times 10 is 60
7 0
3 years ago
Read 2 more answers
Answer maths problem
Evgen [1.6K]

Answer:

200g plain flour

150g almonds

225g sugar

150g butter

Step-by-step explanation:

80g÷4×10

60g÷4×10

90g÷4×10

60g÷4×10

4÷4×10

4 0
2 years ago
Read 2 more answers
Write each Percent as a decimal and as a mixed number or fraction in simplest form
sveticcg [70]

p\%=\dfrac{p}{100}\\\\225\%=\dfrac{225}{100}=2\dfrac{25}{100}=2.25=2\dfrac{1}{4}\\\\550\%=\dfrac{550}{100}=\dfrac{55}{10}=5\dfrac{5}{10}=5.5=5\dfrac{1}{2}\\\\0.8\%=\dfrac{0.8}{100}=\dfrac{0.8\cdot10}{100\cdot10}=\dfrac{8}{1,000}=0.008=\dfrac{1}{125}\\\\0.06\%=\dfrac{0.06}{100}=\dfrac{0.06\cdot100}{100\cdot100}=\dfrac{6}{10,000}=0.0006=\dfrac{3}{5,000}

6 0
3 years ago
Can someone please help me ASAP
forsale [732]

Answer:

its B

Step-by-step explanation:

8 0
3 years ago
After 200 feet of drilling on the first well, a soil test is taken. The probabilities of finding the particular type of soil ide
dimaraw [331]

Answer:

The revised probabilities are;

The probability of finding soil with oil  = 0.8  

The probability of finding soil with good oil = 0.16

The probability of finding medium quality oil =  0.64

Step-by-step explanation:

The given probability of finding soil with high quality oil, P(QO) = 0.20

The probability of finding soil with medium-quality oil, P(OM) = 0.80

The probability of finding soil with no oil, P(ON) = 0.2

Therefore, given that the probability of finding soil with no oil = 0.2, we have;

The probability of finding soil with oil, P(OP) = 1 - the probability of finding soil with no oil

P(OP) = 1 - 0.2 = 0.8

Which gives;

The probability, P(FG) of finding soil with oil and that the oil is good is given as follows;

P(FG) = P(QO) × P(OP) = 0.2 × 0.8 = 0.16

The probability of finding good oil = 0.16

Similarly;

The probability of finding medium quality oil P(FM) =  P(OM) × P(OP) = 0.8 × 0.8 = 0.64

Which gives the revised probability as follows;

The probability of finding soil with oil, P(OP) = 0.8  

The probability of finding soil with good oil, P(FG) = 0.16

The probability of finding medium quality oil, P(FM) =  0.64.                

3 0
3 years ago
Other questions:
  • At a speed of 22 revolutions per minute, how long will it take a wheel of radius 10, rolling on its edge, to travel 10 feet? (As
    12·1 answer
  • Look at the following set of data.
    8·2 answers
  • Which expression is equivalent to 60x^20 y^24/30x^10 y^12?
    5·1 answer
  • Write a verbal sentence for <br> N-8=16
    13·1 answer
  • What is the value of +(-3) 0) (-3)​
    6·1 answer
  • I WILL GIVE BRAINLIEST TO FIRST RIGHT ANSWER
    7·1 answer
  • True or false, there is a decimal point on every whole number. We just don’t usually write it.
    6·2 answers
  • I think I’m missing something
    7·2 answers
  • The question is in the picture, please help me!
    15·1 answer
  • Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!