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Feliz [49]
3 years ago
14

A student buys a rope at the store. The label on the packaging says that the rope is 2.15 meters in length. The student measures

the rope as 1.85m. What is the student’s percent error?
Chemistry
1 answer:
Naily [24]3 years ago
3 0

Answer:

30 center meters

Explanation:

2.15-1.85=0.30

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PLEASE HELP WITH CHEMISTRY !! BRAINLIEST AND 10 POINTS !!
NeTakaya

Answer:

c is your answer there u go

Explanation:

7 0
3 years ago
A chemist sets up a chemical reaction but finds that none of the reactant molecules have a required activation energy. What is t
Anvisha [2.4K]

Activation energy is the minimum amount of energy that the colliding reactant molecules must possess for the formation of products. Lower the activation energy, higher will be chance of formation of products. So activation energy is the minimum energy requirement that has to overcome for the reaction to be completed. Therefore, when in a chemical reaction the reactant molecules do not collide with required activation energy, the collisions will not be fruitful even if they are properly oriented which means that the products will not form.

Hence the correct answer will be B.) no products will be formed

5 0
3 years ago
Read 2 more answers
calculate the volume of carbon dioxide of room temperature and pressure obtained from 30 grams of glucose​
ivanzaharov [21]

Answer:

A

Explanation:

4 0
3 years ago
From the following balanced equation,
ArbitrLikvidat [17]

Answer:

9.72 grams.

Explanation:

From the equation, 4 moles of NH₃ produce 6 moles of  water.

Therefore the reaction to product ratio of  NH₃ to H₂O is 4:6

and 2:3 into its simplest form.

The number of moles of NH₃ in 6.12 g is:

Number of moles=mass/ RMM

=6.12 g/17 G/mol

=0.36 moles.

Therefore the number of moles of H₂O produced is calculated as follows.

(0.36 Moles×3)2 = 0.54 moles

Mass= Number of moles × RMM

=0.54 moles×18g/mol

=9.72 grams.

6 0
3 years ago
56.5 g of sodium nitrate is dissolved in water to make 627 g of solution . what is the percent sodium nitrate in the solution
Tamiku [17]

Answer:

9.01%

Explanation:

The following data were obtained from the question:

Mass of sodium nitrate, NaNO3 = 56.5g

Mass of solution = 627g

The percentage composition of sodium nitrate, NaNO3 in the solution can be obtained as follow:

Percentage composition of NaNO3 = Mass of NaNO3/mass of solution x 100

Percentage composition of NaNO3 = 56.5/627 x 100 = 9.01%

Therefore, the percentage composition of sodium nitrate, NaNO3 in the solution is 9.01%

8 0
3 years ago
Read 2 more answers
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