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liraira [26]
3 years ago
6

In everyday speech the words precision and accuracy are often used interchangeably. When these terms are used in science are the

ir meanings the same as their everyday meanings?
Chemistry
1 answer:
padilas [110]3 years ago
3 0

Answer:

            No, in science their meanings are not the same as their everyday meanings.

Explanation:

                   In Science, Precision and Accuracy are defined as,

Accuracy:

               Accuracy is the value which is closest to the known or standard value.

Precision:

                While, Precision is the value of closeness of two measured values to each other.

Example:

             Let suppose in Chemistry Lab you weight an object as 50 g. While the actual weight of that object is 30 g. It means your reading is not accurate.

             On second measurement you find that the object weight is 31 g. This time your reading is not precise.

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Why are alcohols classified as organic compounds?
Maslowich
Rubbing Alcohols are chemical compounds because rubbing alcohol itself is a strecture made up of many different chemicals combinding in a compound that make,  C3H8O
5 0
3 years ago
There is a gas at 780 mm of Hg, in a volume of 5 liters and a temperature of 37 ​ C, the volume is changed to 5.5 liters and the
HACTEHA [7]

Answer:

32.8 C

Explanation:

- Use combined gas law formula and rearrange.

- Hope that helped! Please let me know if you need further explanation.

6 0
3 years ago
Write the Henderson-Hasselbalch equation for a propanoic acid solution (CH3CH2CO2H, pKa = 4.874) using the symbols HA and A–, an
Luden [163]
The Henderson-Hasselbalch approximation is for conjugate acid-base pairs in a buffered solution. We're going to call HA a weak acid, and A- its conjugate base. The equation is as follows:
pH = pKa + log([base]/[acid]), where the brackets imply concentrations
Plugging in our symbols and the pKa value, the equation becomes:
pH = 4.874 + log([A-]/[HA])
7 0
3 years ago
Identify and name the global<br> wind belts.<br> A<br> B<br> C<br> D<br> E<br> F<br> G
Finger [1]

Answer:

A. Polar Easterlies

B. Westerlies

C. Northeast Trades

D. Southeast Trades

E. Westerlies

F. Polar Easterlies

G. Hadley cell

Explanation:

I am pretty sure this is right. Hope that helps

8 0
3 years ago
Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co
amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as p_{d} and the proportion of air that is by-passed as p_{bp}, being p_{d}+p_{bp}=1.

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

0.004 = 0.016*p_{bp}+ 0.002*p_{d}

Replacing the first equation in the second one we have

0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

7 0
3 years ago
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