Continuing education opportunities allow adults to improve their skills, complete their education and also to change careers.
Answer: Option D
<u>Explanation:
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As we continue our education for higher studies we can learn new things. We can improve our skills by going for higher studies. Some people have a break in their education and they can also continue their education after sometime to complete their course.
So, it helps them to cater their needs and enhance their knowledge. Also when we go for higher studies, we get to know other things about the subject and can try for different career choices. Also, we can even change our ongoing career if we go for higher education and find some other career more interesting and profitable than the existing ones.
One of the formulas for calculating electrical power is
Power = (voltage)² / (resistance)
Since this problem wants us to find the voltage, let's
re-arrange the formula.
Multiply each side by (resistance):
(Voltage)² = (power) x (resistance)
Take the square root of each side:
Voltage = √ (power x resistance)
THERE's the formula we can use to find the voltage for this problem.
Voltage = √ (2,083 W x 25.4 Ω)
Voltage = √ (52,908.2 W-Ω )
Voltage = 230 volts
Answer:
Angular displacement before it stops = 18 rev
Explanation:
Given:
Speed of fan w(i) = 6 rev/s
Speed of fan (Slow) ∝ = 1 rev/s
Final speed of fan w(f) = 0 rev/s
Find:
Angular displacement before it stops
Computation:
w(f)² = w(i) + 2∝θ
0² = 6² + 2(1)θ
0 = 36 + 2θ
2θ = -36
Angular displacement before it stops = -36 / 2
θ = -18
Angular displacement before it stops = 18 rev
One of the concepts to be used to solve this problem is that of thermal efficiency, that is, that coefficient or dimensionless ratio calculated as the ratio of the energy produced and the energy supplied to the machine.
From the temperature the value is given as

Where,
T_L = Cold focus temperature
T_H = Hot spot temperature
Our values are given as,
T_L = 20\° C = (20+273) K = 293 K
T_H = 440\° C = (440+273) K = 713 K
Replacing we have,



Therefore the maximum possible efficiency the car can have is 58.9%
Answer:
El uso mas común de la energía potencial gravitacional, se da en los objetos cercanos a la superficie de la Tierra donde la aceleración gravitacional, se puede presumir que es constante y vale alrededor de 9.8 m/s2.
Explanation: