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Elodia [21]
3 years ago
9

How does a body move if it's constantly under force?

Physics
2 answers:
Anika [276]3 years ago
8 0

so,you know how when someone pushes you, right?

Thats Bascicly whats happening there.

The Force is Moving You Because You Cant Stay As Still As A Staue

When The Force Is Pushing You.

Inessa [10]3 years ago
3 0

If a constant force is applied on a body, the body moves with constant acceleration.

You might be interested in
Which chart provides the correct number of neutrons for each isotope of tin (Sn)?
Trava [24]
We know, Atomic mass = Atomic number + number of neutrons
Here, Atomic mass - 50 = number of neutrons [ as A.N. = 50 ]

So, According to our info. only option B can be correct, as the difference between atomic mass & number of neutrons is 50, which is atomic number of Tin (Sb)

In short, Your Answer would be Option B

Hope this helps!
6 0
3 years ago
A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker. What is the wavelength of the first (n=1) interfere
Sophie [7]

Answer:

2.00m

Explanation:

All we need to do to find the wavelength of the first intereference maximum is subtract both values we are given.

8.00 - 6.00 = 2.00m

Best of Luck!

5 0
3 years ago
Convert Rev/min to rad/s x 2pie/60?<br><br> Anyone knows this please?
defon

Answer:

Thus, \frac{1 rev}{min} =\frac{2\pi}{60} rad/s

Explanation:

The angular speed is defined as the rate of change of angular velocity.

Its SI unit is rad/s and other units are rev/min or rev/s.

\frac{1 rev}{min } = \frac{1 rev}{60 sec}\\\\1 rev = 2\pi rad\\\\So\\\\\frac{1 rev}{min} = \frac{2\pi}{60} rad/s

8 0
3 years ago
To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T
Fantom [35]

Answer:

V_1= 3.4*10^7m/s

Explanation:

From the question we are told that

Nucleus diameter d=5.50-fm

a 12C nucleus

Required kinetic energy K=2.30 MeV

Generally initial speed of proton must be determined,applying the law of conservation of energy we have

            K_2 +U_2=K_1+U_1

where

K_1 =initial kinetic energy

K_2 =final kinetic energy

U_1 =initial electric potential

U_2 =final electric potential

mathematically

   U_2 = \frac{Kq_pq_c}{r_2}

where

r_f=distance b/w charges

q_c=nucleus charge =6(1.6*10^-^1^9C)

K=constant

q_p=proton charge

Generally kinetic energy is know as

         K=\frac{1}{2}  mv^2

Therefore

         U_2 = \frac{Kq_pq_c}{r_2} + K_2=\frac{1}{2}  mv_1^2 +U_1

Generally equation for radius is d/2

Mathematically solving for radius of nucleus

         R=(\frac{5.50}{2}) (\frac{1*10^-^1^5m}{1fm})

         R=2.75*10^-^1^5m

Generally we can easily solving mathematically substitute into v_1

   q_p=6(1.6*10^-^1^9C)

   K_1=9.0*10^9 N-m^2/C^2

   U_1= 0

   R=2.75*10^-^1^5m

   K=2.30 MeV

   m= 1.67*10^-^2^7kg

   V_1= (\frac{2}{1.67*10^-^2^7kg})^1^/^2 (\frac{(9.0*10^9 N-m^2/C^2)*(6(1.6*10^-^1^9C)(1.6*10^-^1^9C)}{2.75*10^-^1^5m+2.30 MeV(\frac{1.6*10^-^1^3 J}{1 MeV}) }

    V_1= 3.4*10^7m/s

Therefore the proton must be fired out with a speed of V_1= 3.4*10^7m/s

8 0
3 years ago
Look around the room you are in. Name
kozerog [31]

Answer:

A wire,rubber

Explanation:

yes

3 0
3 years ago
Read 2 more answers
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