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Scorpion4ik [409]
3 years ago
6

what is the balanced equation that represents the reaction hydrogens and nitrogen to make ammonia (NH3)

Chemistry
1 answer:
KengaRu [80]3 years ago
4 0

Answer: N2 + 3H2 —> 2NH3

Explanation:

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The diagram below shows an electromagnet. Using your scientific knowledge, state the device that is used to measure the potentia
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Voltmeter is the device that is used to measure the potential difference across the battery.

<h2>What are the usage of voltmeter?</h2><h3 /><h3>Usage of Voltmeter</h3>

Voltmeter is an instrument that measures voltages of both direct and alternating electric current. On a scale of voltmeter usually graduated in volts, millivolts (0.001 volt), or kilovolts (1,000 volts).

Voltmeter is connected in parallel form. It has a high resistance so that it takes negligible current from the circuit so we can conclude that Voltmeter is the device that is used to measure the potential difference across the battery.

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Do metals form anions or cations
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Which of the following is a property of matter?
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Explanation:

Matter also exhibits physical properties. Physical properties are used to observe and describe matter. Physical properties can be observed or measured without changing the composition of matter. These are properties such as mass, weight, volume, and density.

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If one parent has sickle cell anemia and the other parent is a carrier, what is the possibility that their child will have sickl
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3 years ago
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
3 years ago
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