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Readme [11.4K]
3 years ago
9

A gas expands from 2.5 L to 8.6 L at a constant temperature. If the initial pressure is 1.6 atm, what is the final pressure?

Chemistry
1 answer:
Burka [1]3 years ago
5 0

Explanation:

the  final pressure  is 0.47 x10^5

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PLEASE HELP!!!
yuradex [85]

This might be right. Im not quite sure. This is what my 5th grade science teacher told me. 'Look at the 2 LR's and add them together. Then look at the total amount which is 32. When you add the 2 LR's you get 17. So subtract 17 from 32 and you get 15. So: C:15 is your answer." (LR's stands for liquid reactants)

10+17=17

Total amount is 32

32-17=15

15 is you mass

Hope this Helps

7 0
3 years ago
Read 2 more answers
What mass of solute should you measure out in order to make 1,000 mL of a 0.3 M solution of magnesium phosphate Mg3(PO4)2?
vivado [14]

Hey there !

Molecular Weight: 262.86 g/mol

Volume in liters : 1,000 mL => 1,000 / 1000 => 1 L

Number of moles of solution :

number of moles = volume x molarity

number of moles = 1 x 0.3  => 0.3 moles

Therefore:

1 mole Mg₃(PO₄)₂ ------------------- 262.86 g

0.3 moles ----------------------------- mass of Mg₃(PO₄)₂  ??

mass of Mg₃(PO₄)₂ = 0.3 x 262.86 / 1

mass of Mg(PO₄)₂ => 78.858 g

Hope this helps!

7 0
3 years ago
Calculate the percentage mass of hydrogen in hydrochloric acid, HCI​
PIT_PIT [208]

Answer:

To find the mass percent of hydrogen in hydrogen chloride, we must divide the weight of the hydrogen atom alone by the weight of the entire molecule. Then we multiply by 100% to find the percentage. Thus, 2.77% of the mass of hydrogen chloride is hydrogen.

Explanation:

i hope you understand better

4 0
3 years ago
When a solution of ammonium chloride, NH4Cl, is added to a solution of lead (II) nitrate , Pb(NO3)2, a white precipitate, PbCl2,
slavikrds [6]

Answer:

B) 2NH_4^+_{(aq)}+2Cl^-_{(aq)}+Pb^{2+}_{(aq)}+2NO_3^-_{(aq)}\rightarrow PbCl_2_{(s)}+2NH^{4+}_{(aq)}+2NO_3^-_{(aq)}

Explanation:

The total ionic equation contains all the species in the reaction in the ionic form.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

Spectator ions are also written in total ionic equations.

The chemical equation is:

2NH_4Cl_{(aq)}+Pb(NO_3)_2_{(aq)}\rightarrow PbCl_2_{(s)}+2NH_4NO_3_{(aq)}

The total ionic equation is -

2NH_4^+_{(aq)}+2Cl^-_{(aq)}+Pb^{2+}_{(aq)}+2NO_3^-_{(aq)}\rightarrow PbCl_2_{(s)}+2NH^{4+}_{(aq)}+2NO_3^-_{(aq)}

5 0
4 years ago
In an experiment, a 0.4351 g sample of benzil (C14H10O2) is burned completely in a bomb calorimeter. The calorimeter is surround
andre [41]

Answer:

The enthalpy change during the reaction is -7020.09 kJ/mole.

Explanation:

First we have to calculate the heat gained by the calorimeter.

q=c\times (T_{final}-T_{initial})

where,

q = heat gained = ?

c = specific heat = 994.1 J/^oC

T_{final} = final temperature = 27.60^oC

T_{initial} = initial temperature = 25.10^oC

Now put all the given values in the above formula, we get:

q=994.1 J/^oC\times (27.60-25.10)^oC

q= 2,485.25 J

The heat gained by water present in calorimeter. = q'

q'=mc\times (T_{final}-T_{initial})

where,

q' = heat gained = ?

m = mass of water = 1.153\times 10^3 g

c' = specific heat of water = 4.184 J/^oC

T_{final} = final temperature = 27.60^oC

T_{initial} = initial temperature = 25.10^oC

q'=1.153\times 10^3 g\times 4.184 J/^oC\times (27.60-25.10)^oC

q ' = 12,060.38 J

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{Q}{n}

where,

\Delta H = enthalpy change = ?

Q = heat gained = -(q+q') = -(2,485.25 J + 12,060.38 J)= -14,545.63 J

Q = -14.54563 kJ

n = number of moles fructose = \frac{\text{Mass of benzil}}{\text{Molar mass of benzil}}=\frac{0.4351 g}{210 g/mol}=0.002072 mole

\Delta H=-\frac{-14.54563 kJ}{0.002072 mole}=-7020.09 kJ/mole

Therefore, the enthalpy change during the reaction is -7020.09 kJ/mole.

3 0
3 years ago
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