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aleksandr82 [10.1K]
2 years ago
8

Why is most of the mass of an atom in the nucleus

Chemistry
2 answers:
nirvana33 [79]2 years ago
5 0

Answer:

The nucleus contains the majority of an atom's mass because protons and neutrons are much heavier than electrons, whereas electrons occupy almost all of an atom's volume. The diameter of an atom is on the order of 10−10 m, whereas the diameter of the nucleus is roughly 10−15 m—about 100,000 times smaller.

Explanation:

hope it helps you

Mrrafil [7]2 years ago
5 0
This is because protons and neutrons are heavier than electrons as opposed to where electrons occupy most of an atoms volume
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A compound contains 6.0 g of carbon and 1.0 g of hydrogen and has a molar mass of 42.0 g/mol.
makvit [3.9K]

Answer:

%C = 85.71 wt%; %H = 14.29 wt%; Empirical Formula => CH₂; Molecular Formula => C₃H₆

Explanation:

%Composition

Wt C = 6 g

Wt H = 1 g

TTL Wt = 6g + 1g = 7g

%C per 100wt = (6/7)100% = 85.71 wt%

%H per 100wt = (1/7)100% = 14.29 wt % or, %H = 100% - %C = 100% - 85.71% = 14.29 wt% H

What you should know when working empirical formula and molecular formula problems.

Empirical Formula=> <u>smallest</u> whole number ratio of elements in a compound

Molecular Formula => <u>actual</u> whole number ratio of elements in a compound

Empirical Formula Weight x Whole Number Multiple = Molecular Weight

From elemental %composition values given (or, determined as above), the empirical formula type problem follows a very repeatable pattern. This is ...

% => grams => moles => ratio => reduce ratio => empirical ratio

for determination of molecular formula one uses the empirical weight - molecular weight relationship above to determine the whole number multiple for the molecular ratios.

Caution => In some 'textbook' empirical formula problems, the empirical ratio may contain a fraction in the amount of 0.25, 0.50 or 0.75. If such an issue arises, multiply all empirical ratio numbers containing 0.25 and/or 0.75 by '4'  to get the empirical ratio and multiply all empirical ration numbers containing 0.50 by '2' to get the final empirical ratio.

This problem:

Empirical Formula:

Using the % per 100wt values in part 'a' ...

              %     =>         grams                 =>                 moles

%C => 85.71% => 85.71 g* / 100 g Cpd => (85.71 / 12) = 7.14 mol C

%H => 14.29% => 14.29 g / 100 g Cpd => (14.29 / 1) = 14.29 mol H

=> Set up mole Ratio and Reduce to Empirical Ratio:

mole ratio C:H =>  7.14 : 14.29

<u>To reduce mole values to the smallest whole number ratio,  divide all mole values by the smaller mole value of the set.</u>

=> 7.14/7.14 : 14.29/7.14 => Empirical Ration=> 1 : 2

∴ Empirical Formula => CH₂

Molecular Formula:

(Empirical Formula Wt)·N = Molecular Wt => N = Molecular Wt / Empirical Wt

N = 42 / 14 = 3 => multiply subscripts of empirical formula by '3'.

Therefore, the molecular formula is C₃H₆

3 0
3 years ago
The compound, nah2po4, is present in many baking powders. what is its name? sodium phosphate sodium bephosphate sodium dihydroge
AlladinOne [14]
 The  compound NaH2PO4     name  is

sodium  dihydrogen  phosphate

 
Explanation
This name is    arrived  at  by using the   IUPAC rules  of naming   compound

1.  the metal (sodium)is  named  first  followed  by  the ligand ( hydrogen  and phosphate)

Ligand  are  molecules   that are   attached to  the metal  center.

2.   ligand  are  named using alphabetical   order(for  our  case  h  for hydrogen come before p for  phosphate hence hydrogen is named first)

3. Prefix   di is used  since hydrogen  are two

hence the name  of the compound  is  Sodium dihydrogen  phosphate


8 0
3 years ago
What is the acceleration of a 50 kg object pushed with a force of 500 newtons?
son4ous [18]

Answer:

F = MA

500 = 50 multiply by A

A= 500/50

A= 10m/s2

3 0
3 years ago
Can someone answer an easy chemistry question? A chemistry grad student measures the performance of the new pump in his lab. The
ella [17]
This problem requires our calculation to undergo the dimensional analysis approach. In this approach, you disregard the actual quantity and focus on the units of measurement. This helps us know the units of our final answer. 

First, let's ignore 16. Let's focus on converting the units kPa-mm³/s to mJ/s. The unit kPa stands for kiloPascals which is 1000 times greater than 1 Pa. The unit mJ, on the other hand, stands for millijoules, which is 1000 times lesser than Joules. The relationship between the two is that, Joules = Pa × m³. But since we want our final answer to be mJ, that would be equal to Pa×mm³. Since the original unit already contains mm³, all we have to do is convert kPa to Pa. 

16 kPa-mm³/s * (1000 Pa/1 kPa) = 16,000 Pa-mm³/s

Since Pa-mm³ is equal to mJ, the final conversion yields to 16,000 Pa-mm³/s.
7 0
3 years ago
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Consider the unbalanced equation for aluminum and oxygen producing aluminum oxide: Al + O₂ → Al₂O₃. Which of the following shows
DIA [1.3K]

Answer:

A answer is correct that help

6 0
3 years ago
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