Answer:
323 m/s²
Explanation:
Given:
x₀ = 0 m
y₀ = 0 m
x = 29500 cos 65°
y = 29500 sin 65°
v₀x = 1810 cos 20°
v₀y = 1810 sin 20°
t = 9.20
Find:
ax, ay, θ
First, in the x direction:
x = x₀ + v₀ t + ½ at²
29500 cos 32° = 0 + (1810 cos 20°) (9.20) + ½ ax (9.20)²
25017 = 15648 + 42.32 ax
ax ≈ 221.4
And in the y direction:
y = y₀ + v₀ t + ½ at²
29500 sin 32° = 0 + (1810 sin 20°) (9.20) + ½ ay (9.20)²
15633 = 5695 + 42.32 ay
ay ≈ 234.8
Therefore, the magnitude of the acceleration is:
a² = ax² + ay²
a² = (221.4)² + (234.8)²
a ≈ 322.7
Rounded to 3 significant figures, the magnitude of the acceleration is approximately 323 m/s².
The product of mass and velocity is momentum. P=mv. The 'P' in the equation stands for momentum.
is the period of orbit.
<u>Explanation:
</u>
The equation that is useful in describing satellites motion is Newton form after Kepler's Third Law. The period of the satellite (T) and the average distance to the central body (R) are related as the following equation:
Where,
T is the period of the orbit
R is the average radius of orbit
G is gravitational constant 
Here, given data
Substitute the given values, we get T as
Taking square root, we get
Answer:
The time constants 30 seconds and the can form an RC Charging circuit.
Explanation:
Time constant, τ, is measured in terms of τ = R x C, in seconds, where R is the value of the resistor in ohms and C is the value of the capacitor in Farads
If R = 150 kΩ = 150000Ω
and C = 200 μF = 0.0002 F
τ = 150,000 × 0.0002
<u>= 30 seconds.</u>
A capacitor, (C) connected in series with a resistor, (R) forms a RC Charging Circuit connected across a DC battery supply (Vs) via a mechanical switch, with transient time (time required to charge capacitor) = 5τ
