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Vsevolod [243]
4 years ago
6

How is the pressure exerted and the area on which it is exerted are related to each other?

Physics
1 answer:
andrezito [222]4 years ago
3 0
Pressure = force/area
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After a nucleus with 85 protons undergoes alpha decay, it has<br><br> ? protons.
Valentin [98]

Answer:

After a nucleus with 85 protons undergoes alpha decay, it has  83 protons.

Explanation:

In an alpha particle there are two protons

In the given substance's nucleus, there are total of 85 protons

After the decay, the proton number reduce

The current proton number after decay is

85 -2 = 83

After a nucleus with 85 protons undergoes alpha decay, it has  83 protons.

5 0
3 years ago
With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the botto
Dvinal [7]

The speed of the car at the bottom of the hill is obtained as, v = \sqrt{2gh}

According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.

K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v= \sqrt{2gh}

where;

  • <em>v </em><em>is the speed of the car at the bottom of the hill</em>
  • <em>h </em><em>is the height of the hill</em>
  • <em>g </em><em>is acceleration due to gravity</em>

Thus, the speed of the car at the bottom of the hill is obtained as, v = \sqrt{2gh}

Learn more about conservation mechanical energy here: brainly.com/question/332163

3 0
3 years ago
Is there such a thing as real time weather radar ? why not?
Troyanec [42]
No because the whether changes constant, weather can be close but is not the 100% the correct answer,..
5 0
4 years ago
a spring gun initially compressed 2cm fires a 0.01kg dart straight up into the air. if the dart reaches a height it 5.5m determi
Vikki [24]

Answer:

2697.75N/m

Explanation:

Step one

This problem bothers on energy stored in a spring.

Step two

Given data

Compression x= 2cm

To meter = 2/100= 0.02m

Mass m= 0.01kg

Height h= 5.5m

K=?

Let us assume g= 9.81m/s²

Step three

According to the principle of conservation of energy

We know that the the energy stored in a spring is

E= 1/2kx²

1/2kx²= mgh

Making k subject of formula we have

kx²= 2mgh

k= 2mgh/x²

k= (2*0.01*9.81*5.5)/0.02²

k= 1.0791/0.0004

k= 2697.75N/m

Hence the spring constant k is 2697.75N/m

7 0
3 years ago
Please help me on this question, it would mean a lot! Thank you! Only question one, thank you
Akimi4 [234]
The answer to your question is SPEED.
3 0
4 years ago
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