How is the pressure exerted and the area on which it is exerted are related to each other?

a load of 45 N attached to a spring that is hanging vertically stretches the spring 0.14 m. What is the spring constant?

zhenek [66]

According to Hooke's law, Force = spring constant x displacement of the spring. Spring constant = Force/displacement in spring = 45/0.14 = 321.42 N/m. Hope this helps!

3 0

3 years ago

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Radiation in the ultraviolet region of the electromagnetic spectrum is quite energetic. It is this radiation that causes dyes to

N76 [4]

The energy of photon in kJ/mol is 329kJ/mol.

Wavelength of radiation is 370nm. The frequency of given wavelength is

ν = c / λ

ν = 3×10^8 / 370×10^-9

ν = 8.11 × 10^14 s^-1

Now the energy of photon is:

E = hν

E = 6.63×10^-34 J.s/photon × 8.11×10^14s^-1

E = 5.41× 10^-19 J/photon

To find in mole

E = 5.41× 10^-19 × 6.022×10^23

E = 3.29 ×10^ 5 J/mol

So, the energy of mole of photon is equal to 329 kJ/mol.

Learn more about radiation here:

brainly.com/question/18650102

#SPJ4

5 0

1 year ago

Matter is anything that has

Svetlanka [38]

Answer:

Space

Explanation:

Hope this helped

8 0

3 years ago

Earl _______ go to the game today.* cantcan'tcan 'ntcant'

mariarad [96]

Can't

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3 years ago

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In 1932 Albert Dremel of Racine, Wisconsin, created his rotary tool that has come to be known as a dremel.

kramer

Answer:

3054.32618 rad/s²

-431.1989 rad/s²

29080

Explanation:

Converting angular speed to rad/s

$\omega=35000\times \frac{2\pi}{60}=3665.19142\ rad/s$

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{3665.19142-0}{1.2}\\\Rightarrow a=3054.32618\ rad/s^2$

The average acceleration while speeding up is 3054.32618 rad/s²

The number of turns in the 1.2 seconds

$\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\frac{1}{2}\times 3054.32618\times 1.2^2\\\Rightarrow \theta=2199.11484\ rad=\frac{2199.11484}{2\pi}=349.99\ rotations$

The number of rotations in the 1.2 seconds is 349.99

Number of rotations in the 45 seconds

$\frac{35000}{60}\times 45=26250\ rotations$

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-3665.19142}{8.5}\\\Rightarrow a=-431.1989\ rad/s^2$

Average angular acceleration while slowing down -431.1989 rad/s²

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-3665.19142^2}{2\times -431.1989}\\\Rightarrow \theta=15577.0668\ rad=\frac{15577.0668}{2\pi}\\ =2479.16718\ rotations$

Number of rotations while slowing down is 2479.16718

Total number of rotations is 349.99+26250+2479.16718 = 29079.15718 = 29080

3 0

2 years ago