Answer:
Approximately 
(assuming that 
.)
Explanation:
Let 
denote the force that this spring exerts on the object. Let 
denote the displacement of this spring from the equilibrium position.
By Hooke's Law, the spring constant 
of this spring would ensure that 
.
Note that the mass of the object attached to this spring is 
. Thus, the weight of this object would be 
.
Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, 
.
The spring in this question was stretched downward from its equilibrium by:
.
(Note that is negative since this displacement points downwards.)
Rearrange Hooke's Law to find in terms of and :
.
False
-A magnet can never have one pole, even a simple magnet was cut, each end would have an opposite south(-) or north(+) pull.
-This is the result of moving electrons
Answer:
(a) 0.17 m
(b) 5.003 m
(c) 6.38 × 
N
(d) 7.37 ×
N
Explanation:
(a) The minimum value of will occur when q3 = 0 m or at origin and q1, q2 are at 0.17 m so the distance between q3 and q1, q2 is 0.17 m, therefore the <em>minimum value of x= 0.17 m</em>.
(b) The maximum value of x will occur when q3 = 5 m because it is said in the question that 5 is the maximum distance travelled by q3. To find the hypotenuse i.e. the distance between q3 and q1,q2, we use Pythagoras theorem.
<em>Hence, the maximum distance is 5.002 m</em>
(c) For minimum magnitude we use the minimum distance calculated in (a)
Minimum Distance = 0.17 m
For electrostatic force= 
×
(d) For maximum magnitude, we use the maximum distance calculated in (b)
Maximum Distance = 5.002 m
Using the formula for electrostatic force again:
F = 
F= 7.37×
N
When a liquid is cooled, the kinetic energy of the particles, DECREASES..
