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Ghella [55]
3 years ago
14

A 200-kilogram wood crate is pushed across a wood floor How much force will be needed to move the box at a constant velocity of

0.5 m/s
Physics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

100N

Explanation:

F = m x a

m = 200kg

a = 0.5m/s

F = 200 x 0.5

F = 100

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hram777 [196]

All the radiation from stars is the result of nuclear fusion in their cores.

4 0
3 years ago
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The momentum of a falling rock is found to be 200 kg m/s. What is the mass of the rock if it falls with a velocity of 5.0 m/s
Snezhnost [94]

Answer:

\boxed {\boxed {\sf 40 \ kilograms}}

Explanation:

Momentum is the product of velocity and mass. The formula is:

p=m*v

We know the rock is falling. Its momentum is 200 kilograms meters per second and its velocity is 5 meters per second. Substitute the values into the formula.

200 \ kg \ m/s = m * 5.0 \ m/s

We are solving for m, the mass. We must isolate the variable. It is being multiplied by 5 meters per second. The inverse of multiplication is division, so we divided both sides by 5.0 m/s.

\frac{200 \ kg \ m/s}{5.0 \ m/s}=\frac{ m* 5.0 \ m/s }{5.0 \ m/s}

\frac{200 \ kg \ m/s}{5.0 \ m/s}=m

The units of meters per second (m/s) cancel.

\frac{200 \ kg}{5.0 } =m

40 \ kg = m

The falling rock has a mass of <u>40 kilograms.</u>

4 0
3 years ago
Calculate the magnitude and direction of the electric field 2.0 m from a long wire that is charged uniformly at λ = 4.0 × 10-6 C
Len [333]

Answer: 71.93 *10^3 N/C

Explanation: In order to calculate the electric field from long wire we have to use the Gaussian law, this is:

∫E*dr=Q inside/εo  Q inside is given by: λ*L then,

E*2*π*r*L=λ*L/εo

E= λ/(2*π*εo*r)= 4* 10^-6/(2*3.1415*8.85*10^-12*2 )= 71.93 * 10^3 N/C

6 0
3 years ago
A volumetric flow rate of 2 m^3/ s of liquid water is to be pumped from sea level to an elevation of 1200 m. Taking the density
exis [7]

Answer:

power requirement is 23.52 × 10^{6}  W

Explanation:

given data

flow rate q = 2 m³/s

elevation h = 1200 m

density of the water ρ = 1000 kg/m³

to find out

power requirement

solution

we will get power by the power equation that is

power = ρ× Q× g× h   ...................1

put here all value we get power

power = ρ× Q× g× h

power = 1000 × 2 × 9.8 × 1200

power = 23.52 × 10^{6}

so power requirement is 23.52 × 10^{6}  W

6 0
3 years ago
6. several light bulbs are connected in series across a 115 v source
Natalka [10]

Explanation:

a) I = V / R

1.70 = 115 / R

R = 115 / 1.70

R = 67.647

R = 67.65 ohms

Therefore, equivalent resistance is 67.65 ohms

b) Equivalent resistance of circuit from above sum is 67.65 ohms

Given resistance of each bulb is 1.50 ohms

Number bulbs = Equivalent resistance / Resistance of each bulb

= 67.65 / 1.50

= 45

8 0
2 years ago
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