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3 years ago

Where do most water molds and downy wildews live?

Physics

1 answer:

Leokris [45]3 years ago

5 0

Most water molds and/or downy mildews live in the water or in moist places, These organisms usually grow as tiny fuzz.

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What is the formula for silver nitrate

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Answer:

Explanation:

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3 years ago

4:list one food chain that is part of the food web.

Sophie [7]

4. Grass - Caterpillar - Hedgehog - Fox
5. Caterpillar, Rabbit, Mouse.
6. Cougar and Fox.
7. Bacteria
8. The bird, hedgehog, Fox and cougar would be effected since the Hedgehogs and birds would soon die out due to the loss of their food. Once they die out, the cougar and Fox would have no predators left to eat.

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3 years ago

find a magnitude of the force such that if the act at right angle there resultant is √10N but if the act of 50° the resultant is

Readme [11.4K]

Explanation:

Let magnitude of the two forces be x and y.

Resultant at right angle R1= √15N) and at

60 degrees be R2= √18N.

Now, R1 = √(x² + y²) = √15,

R2= √(x² + y² +2xycos50) = √18.

So x² + y² = 15,

and x² + y² + 1.29xy = 18,

therefore 1.29xy = 3,

y = 3/1.29x.

y = 2.33/x

Now, x2 + (2.33/x)2 = 15,

x² + 5.45/x² = 15

multiply through by x²

x⁴ + 5.45 = 15x²

x⁴ - 15x2 + 5.45 = 0

Now find the roots of the equation, and later y. The two values of x will correspond to the

magnitudes of the two vectors.

Good luck

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3 years ago

DESCRIBE THE FORMATION OF THE SOLAR SYSTEM ACCORDING TO THE NEBULAR THEORY

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When a cloud of gas and dust in space was disturbed, maybe by the explosion of a nearby star.This explosion made waves in space which squeezed the cloud of gas & dust.

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3 years ago

A duck swimming on the surface of a pond has an

Gemiola [76]

From the given information:

Taking the movement of the Duck in the North as the x-direction
The movement of the Duck in the East direction as the y-direction

However, we will have to compute the initial velocity and the acceleration of the duck in their vector forms.

<h3>In vector form;</h3>

The initial velocity is:

$\mathbf{u ^{\to} = 0.7 m/s ( -cos 25^0 \hat x + sin 25^0 \hat y ) \ m/s}$

The acceleration is:

$\mathbf{a ^{\to} = 0.5 m/s ( cos 41^0 \hat x - sin 41^0 \hat y ) \ m/s^2}$

The objective of this question is to determine the speed of the duck at a certain time. Since it is not given, let's assume we are to determine the Duck speed after 4 seconds of accelerating;

Then, it implies that time (t) = 4 seconds.

Using the first equation of motion:

$v^{\to} = u ^{\to} + a^{\to} t$

Then, we can replace their values into the equation of motion in order to determine the speed:

$\mathbf{v^{\to} =\Big(0.7 ( -cos 25^0 \hat x + sin 25^0 \hat y )+4 \times 0.5 ( cos 41^0 \hat x - sin 41^0 \hat y )\Big)}$

$\mathbf{v^{\to} =\Big(0.7 ( -cos 25^0 \hat x + sin 25^0 \hat y )+2.0 ( cos 41^0 \hat x - sin 41^0 \hat y )\Big)}$

$\mathbf{v^{\to} =\Big( ( -0.7 cos 25^0 \hat x + 0.7 sin 25^0 \hat y )+( 2.0cos 41^0 \hat x - 2.0sin 41^0 \hat y )\Big)}$

Collect like terms:

$\mathbf{v^{\to} =\Big( (2.0cos 41^0 -0.7 cos 25^0 )\hat x+( 0.7 sin 25^0 - 2.0sin 41^0 )\Big)\hat y}$

$\mathbf{v^{\to} =0.87500 \hat x- 1.01629 \hat y}$

Thus, the magnitude is:

$\mathbf{v^{\to} =\sqrt{(0.87500 )^2 +( 1.01629 )^2}}$

$\mathbf{v^{\to} =\sqrt{0.76563 +1.03285}}$

$\mathbf{v^{\to} =\sqrt{1.79848}}$

$\mathbf{v^{\to} =1.34 \ m/s}$

Therefore, we can conclude that the speed of the duck after 4 seconds is 1.34 m/s

Learn more about vectors here:

brainly.com/question/17108011?referrer=searchResults

4 0

3 years ago