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3 years ago

What important factor does the ozone layer serve in earth's atmosphere?

1 answer:

3 0

The Ozone layer is responsible for the absorption of harmful radiation from the sun before it hits the surface or exterior structure of our planet. It is known to be a belt of a known occurring gas, known as “ozone” which is sealed around the Earth’s atmosphere. It serves as a shield, which absorbs most of the sun’s ultraviolet radiation.

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Trees are planned in roads to reduce noise. Justify the statement

Serjik [45]

According to how I understand it ,trees helps to create a visual barrier between the source of the noice and the hearer , it roots helps to reduce the sound waves by absorbing

7 0

3 years ago

A 49.6-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.584 and 0.399,

NISA [10]

Answer:

(a) Force must be grater than 283.87 N

(B) Force will be equal to 193.945 N

Explanation:

We have given mass of the crate m = 49.6 kg

Acceleration due to gravity $g=9.8m/sec^2$

Coefficient of static friction $\mu _s=0.584$

Coefficient of kinetic friction $\mu _k=0.399$

(a) Static friction force is given by $F_S=\mu _smg=0.584\times 49.6\times 9.8=283.8707N$

So to just start the crate moving we have to apply more force than 283.87 N

(B) This force will be equal to kinetic friction force

We know that kinetic friction force is given by $F_k=\mu _kmg=0.399\times 49.6\times 9.8=193.945N$

3 0

3 years ago

Hi please help with this question! Need the workings.

andreyandreev [35.5K]

Mass of the copper penny m = 2.6 g Atomic mass of copper = 63.55, Atomic number = 29, So the number of neutrons = Atomic mass - Atomic number = 63 - 29 = 34 a. Neutron mass = 34 x (2.6 / 63.55) = 1.4 grams Copper atoms per mole = 6.040 x 10^23 atoms/mol moles of copper = 2.6 / 63.06 = 0.04123 mol Total atoms in the copper = 6.040 x 10^23 atoms/mol x 0.04123 mol = 0.25 x 10^23 atoms Number of electrons in the copper = 29 per atom Mass of the electron = 9.085 x 10^-28 g b. Electron mass = 0.25 x 10^23 x 29 x 9.085 x 10^-28 = 65.86 x 10^-5 g

6 0

3 years ago

Clasifica los siguientes enunciados de acuerdo a si se describen movimientos

Alenkasestr [34]

Answer:

- translation

- rotation, traslation

- traslation, rotation

- vibrating

Explanation:

El movimiento de un cuerpo cae por su propio peso traslación.

El movimiento de las ruedas de una bicicleta al ser pedaleada rotación, traslación.

El movimiento de la Tierra alrededor de sol traslación, rotación.

El movimiento de la cuerda de una guitarra cuando se está tocando música vibración.

- - - - - - - - - - - - - - - - - - - - - - - - - - - -

The movement of a body falls under its own weight translation.

The movement of the wheels of a bicycle when being pedaled rotation, translation.

The movement of the Earth around the sun, translation, rotation.

The movement of a guitar string when playing music vibrating.

7 0

3 years ago

A concave mirror has a focal length of 11 cm . What is its radius of curvature?

OverLord2011 [107]

Answer:

22cm

Explanation:

focal length = 11cm

radius of curvature,r = 2f

r= 2 x 11

r=22cm

6 0

3 years ago