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Softa [21]
3 years ago
15

Two boys wearing roller skates are standing on a smooth surface with the palms of their hands touching and their arms bent, as s

hown above. if boy x pushes by straightening his arms out while boy y holds his arms in the oringinal position, what is the motion of the two boys
Physics
1 answer:
vlada-n [284]3 years ago
8 0

Boy X and Boy Y both move backward in opposite directions.
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Answer: 14. 49 m

Explanation:

We can solve this problem with the following equations:

x=V_{o} cos \theta t (1)

y-y_{o}=V_{o} sin \theta t-\frac{1}{2}gt^{2} (2)

Where:

x is the horizontal distance between the cannon and the ball

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t is the time

y=0 is the final height of the cannonball

y_{o}=1.96 m is the initial height of the cannonball

g=9.8 m/s^{2} is the acceleration due gravity

Isolating t from (2):

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Substituting (5) in (1):

x=(23 m/s) cos(0\°) 0.63 s (6)

Finally:

x=14.49 m

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