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Lana71 [14]
3 years ago
9

Anybody know the answer to this ?

Physics
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:

4 ampere

Explanation:

I= v/R

=12/3

= 4 amp

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A monatomic gas is adiabatically compressed to 0.250 of its initial volume. Do each of the following quantities change?
Len [333]

Answer:

Given that

V2/V1= 0.25

And we know that in adiabatic process

TV^န-1= constant

So

T1/T2=( V1 /V2)^ န-1

So = ( 1/0.25)^ 0.66= 2.5

Also PV^န= constant

So P1/P2= (V2/V1)^န

= (1/0.25)^1.66 = 9.98

A. RMS speed is

Vrms= √ 3RT/M

But this is also

Vrms 2/Vrms1= (√T2/T1)

Vrms2=√2.5= 1.6vrms1

B.

Lambda=V/4π√2πr²N

So

Lambda 2/lambda 1= V2/V1 = 0.25

So the mean free path can be inferred to be 0.25 times the first mean free path

C. Using

Eth= 3/2KT

So Eth2/Eth1= T2/T1

So

Eth2= 2.5Eth1

D.

Using CV= 3/2R

Cvf= Cvi

So molar specific heat constant does not change

5 0
3 years ago
Read 2 more answers
Which component measures the potential difference across a branch in a circuit? A.switch. B.resistor. C.ammeter. D.voltmeter.
Mademuasel [1]

Answer: The correct answer is option (D).

Explanation:

Voltmeter is a device which measures the the voltage applied across the circuit. It is an electrical instrument used to measure the electric potential between the two points in an electric circuit.

Where as:

A switch is the device which used to connect or disconnect the circuit.

Resistor is a device which opposes the flow of current is an electric circuit.

An ammeter the is an electrical device which measures the amount of current in flowing in amperes in an electrical circuit

Hence,the correct answer is option (D).

4 0
3 years ago
Read 2 more answers
A sprinf has a potential energy of 84.08 J and a constant of 342.25 N/m. How far it been stretched? Use potential energy elastic
valina [46]

The spring has been stretched 0.701 m

Explanation:

The elastic potential energy of a spring is the potential energy stored in the spring due to its compression/stretching. It is calculated as

E=\frac{1}{2}kx^2

where

k is the spring constant

x is the elongation of the spring with respect to its equilibrium position

For the spring in this problem, we have:

E = 84.08 J (potential energy)

k = 342.25 N/m (spring constant)

Therefore, its elongation is:

x=\sqrt{\frac{2E}{k}}=\sqrt{\frac{2(84.08)}{342.25}}=0.701 m

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

8 0
3 years ago
Two birds have the same mass but one has bigger feet. How would pressure that they produce on the ground be different ?
Mama L [17]

Answer:

the pressure per square inch is greater from the smaller feet.

Explanation:

different weight distribution

3 0
3 years ago
A 120.0 kg crate is placed on a 15.00°
Citrus2011 [14]

F = 2820.1 N

Explanation:

Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as

Fnet = ma = 0 (a = 0 no sliding)

= F - mgsin15°

= 0

or

F = mgsin15°

= (120 kg)(9.8 m/s^2)sin15°

= 2820.1 N

7 0
3 years ago
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