All categories

3 years ago

What intermolecular force(s) is/are present in solid SO3?

Chemistry

1 answer:

guapka [62]3 years ago

5 0

Answer:

1. London dispersion

Explanation:

Sulphur trioxide ( SO₃ ) -

The chemical compound SO₃ is planar in structure , the only intermolecular forces shown by SO₃ is the London forces .

dipole - dipole is not observed in this compound , as it is not possible to generate poles between the sulfur and oxygen atom due to very less difference in the electronegativity .

Hydrogen bonding is also not observed , because there is not hydrogen atom .

Hence , only London forces are observed in SO₃ .

You might be interested in

What is the difference between a continuous spectrum and a line spectrum? Give a source of each

natima [27]

Continuous spectrum and line spectrum are two types of spectra; their main difference is that continuous spectrum contains no gaps whereas line spectrum contains many gaps.

7 0

2 years ago

HELP ASAP!! FILL IN THE BLANKS! will be brainliest!!!

Ludmilka [50]

Answer:

Don't mark me brainliest because of this but I'm pretty sure your supposed to give us the words because teachers don't give you things like that without the words you will the answer in with.

4 0

3 years ago

Read 2 more answers

When chromium loses two electrons, its configuration changes to A. [Ar]4s13d5. B. [Ar]3d4. C. [Ar]4s13d4. D. [Ar]4s1.

belka [17]

Chromium has the electron configuration [Ar]4s13d5 and exhibits oxidation numbers 2+, 3+, and 6+. When chromium loses two electrons, it forms the Cr2+ ion and has the configuration [Ar]3d4.

The Answer is B. [Ar]3d4

5 0

3 years ago

Helppppp meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Maru [420]

Answer:

The industry represented in the photo is most likely fishing. Other industries that rely on accurate weather forecasts are shrimping, fishery, and aquaculture

Explanation:

6 0

3 years ago

Read 2 more answers

The solubility of silver(I)phosphate at a given temperature is 1.02 g/L. Calculate the Ksp at this temperature. After you get yo

Snezhnost [94]

<u>Answer:</u> The solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

<u>Explanation:</u>

We are given:

Solubility of silver (I) phosphate = 1.02 g/L

To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:

Molar mass of silver (I) phosphate = 418.6 g/mol

$\text{Molar solubility of silver (I) phosphate}=\frac{1.02g/L}{418.6g/mol}=2.44\times 10^{-3}mol/L$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of silver (I) phosphate follows:

$Ag_3PO_4(aq.)\rightleftharpoons 3Ag^{+}(aq.)+PO_4^{3-}(aq.)$

3s s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=(3s)^3\times s$

We are given:

$s=2.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(3\times 2.44\times 10^{-3})^3\times (2.44\times 10^{-3})\\\\K_{sp}=9.57\times 10^{-10}$

Hence, the solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

4 0

3 years ago