Answer is: S<span>AE standard that must be referred to on the label of approved HFC-134a refrigerant recycling machines are </span>J1770 and J2788.
<span>J1770 is to establish the specific minimum equipment requirements for recovery or recycling equipment intended for use with R134a.
</span>J2788 is intended to establish requirements for equipment used to recharge HFC-134a.<span />
Answer:
Yes
Explanation:
The tilt of the Earth means the Earth will lean towards the Sun (Summer) or lean away from the Sun (Winter) 6 months later. In between these, Spring and Autumn will occur. The North pole always points the same way as the Earth revolves around the Sun.
Fires affect animals mainly through effects on their habitat.
Answer:
The product is 1-methylcyclopentanol
Explanation:
The acid-catalyzed hydration of alkenes involves the addition of a water molecule to a C=C double bond.
H₂O + C=C ⟶ H-C-C-OH
An H atom adds to one of the C atoms, and an OH group adds to the other
This reaction follows Markovnikov’s rule — the H adds to the C atom that has more hydrogen atoms, and the OH adds to the more substituted carbon.
The steps of the mechanism are:
- The aqueous sulfuric acid generates hydronium ions
- The nucleophilic π electrons attack an H atom on the hydronium ion, forming a carbocation on the more substituted C atom.
- The lone pair electrons on a water molecule attack the carbocation , forming an oxonium ion.
- Another water molecule removes the extra proton.
The product is the alcohol with the OH group on the more substituted carbon — 1-methylcyclopentanol.
Answer:
Volume of HNO₃ required = 140 mL
Explanation:
Given data:
Molarity of HNO₃ = 0.563 M
mass of BaCO₃ = 7.83 g
Volume of HNO₃ = ?
Solution:
First of all we will write the balance chemical equation
2HNO₃ + BaCO₃ → Ba(NO₃)₂ + H₂O + CO₂
Number of moles of BaCO₃ = mass / molar mass
Number of moles of BaCO₃ = 7.83 g / 197.34 g/mol
Number of moles of BaCO₃ = 0.04 mol
Now we compare the moles of BaCO₃ and HNO₃ .
BaCO₃ : HNO₃
1 : 2
0.04 : 2×0.04 = 0.08 mol
Volume of HNO₃ required = number of moles / Molarity
Volume of HNO₃ required = 0.08 mol / 0.563 mol/L
Volume of HNO₃ required = 0.14 L
0.14 × 1000 = 140 mL
