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Montano1993 [528]
2 years ago
15

Which of the following is true of group 6A?

Chemistry
1 answer:
USPshnik [31]2 years ago
7 0

Answer:

The answer to your question is: Includes sulfur and gain two electrons

Explanation:

Includes Chlorine  This option is wrong, Chlorine belongs to group VII.

Includes Sulfur  This option is true, Group VI includes Oxygen, Sulfur, Selenium, Tellurium.

Gain 2 electrons . This option is true, Elements in group VI have six valence electrons so they gain to electrons to become estable.

Tend to form +2 ions  This option is wrong, this elements form -2 ions

Have 5 valence electrons This option is wrong, this elements have 6 valence electrons.

You might be interested in
How scientists used the scientific method to learn more about how dinosaurs became extinct​
lesya [120]

Answer:

they tested the bone age

Explanation:

4 0
2 years ago
A person struggles very hard to lift a large boulder. He puts in so much effort, he starts to sweat, his heart rate increases, a
Tems11 [23]
No, according to physics no work has been done.

Work must have been done by muscular force but in terms of physics no work has been done.

In physics,work is said to be done only if the force applied produced some kind of displacement in the direction of force.

In this example provided, no work has been done since the boulder doesn't get displaced,it continues to remain at its original position.

Hope This Helps You!
6 0
3 years ago
In methane combustion, the following reaction pair is important: At 1500 K, the equilibrium constant Kp has a value of 0.003691
andre [41]

Explanation:

Let us assume that the value of K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{T}}) m^{6}/mol^{2}s

Also at 1500 K, K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{1500}}) m^{6}/mol^{2}s

                     K_{r} = 400.613 m^{6}/mol^{2}s

Relation between K_{p} and K_{c} is as follows.

                  K_{p} = K_{c}RT

Putting the given values into the above formula as follows.

                  K_{p} = K_{c}RT

         0.003691 = K_{c} \times 8.314 \times 1500

                K_{c} = 2.9 \times 10^{-7}

Also,     K_{c} = \frac{K_{f}}{K_{r}}

or,                K_{f} = K_{c} \times K_{r}

                               = 2.9 \times 10^{-7} \times 400.613

                               = 1.1617 \times 10^{-4} m^{6}/mol^{2}s

Thus, we can conclude that the value of K_{f} is 1.1617 \times 10^{-4} m^{6}/mol^{2}s.

6 0
3 years ago
Calculate the molarity of each of the following
Alenkasestr [34]

Answer:

a. 1.21M

b. 0.119M

c. 0.00496M

Explanation:

Molarity, M, is an unit of concentration defined as the ratio between moles of solute and liters of solution:

a. 4.35 mol LiCl / 3.60L = 1.21M

b. 29.43gC6H12O6 * (1mol / 180.16g) = 0.1634moles / 1.37L = 0.119M

<em>Molar mass C6H12O6: 180.16g/mol</em>

c. 34.5mg NaCl = 0.0345g * (1mol / 58.44g) = 5.9x10⁻⁴moles / 0.1191L = 0.00496M

8 0
2 years ago
Which is the smallest particle into which a compound can be broken down and still remain the same compound? A. atom B. mixture C
Andre45 [30]
The smallest would be a compound
4 0
3 years ago
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