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Law Incorporation [45]
3 years ago
12

You are given sodium acetate, 1m hcl, nahco3 and na2co3. Determine which of these four you would need and then show calculations

to make buffer ph
Chemistry
1 answer:
valentina_108 [34]3 years ago
5 0

solution:

the given compounds are sodium acetate, 1M HCL,NaHCO₃ and Na2CO₃

pH of the buffer solution is 4.7

the value of pKa of sodium bicarbonate is 6.37

the value of pKa of acetic acid is 4.7

calculate concentration of acetic acid by using the following forumula

pH=pKa+lag[salt]/[acid]

substitute the pH and Pka values in the formula.

4.7=4.7+log[salt]/[acid]

log[salt]/[acid]=0

thus, the concentration ratio of the salt and acid should be equal to each other.

Thus, concentration of sodium acetate is 0.05M

Concentration of sodium acetate= concentration of acid

= 0.05M

Volume of the buffer solution is 100mL

The buffer solution can be prepared as 0.05M of 50mL sodium acetate will react with 0.05M of 50mL of 0.05M of HCL.

The chemical equation for neutralization of the weak base with strong can be represented as show as

CH₃COONa+HCL-->CH₃COOH+NaCL


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Two descriptions about physical quantities are given below:
gladu [14]

Answer:

Quantity A is weight and Quantity B is mass

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3 years ago
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What happens when a cell that has an internal salt concentration of 0.15M NaCl is placed into a solution of 0.01M NaCl?
Julli [10]

Answer: the cell will absorb more water which can lead to haemolysis (rising and bursting of the cell)

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3 years ago
How many grams are in 44.8 liters of nitrogen gas, n2?<br> a) 56g<br> b) 27g<br> c) 36g<br> d) 112g
kkurt [141]

a) 56g

<h3>Calculation:</h3>

At STP,

22.4 L of N₂ = 1 mol

We have given 44.8 L of N₂, therefore,

44.8 L of N₂ = \frac{44.8}{22.4}

                    = 2 mol

We know that,

1 mol of N₂ = 28 g

Hence,

2 mol of N₂ = 28 × 2

                   = 56g

Hence, there are 56 g of N₂ in 44.8 L of nitrogen gas.

Learn more about calculation at STP here:

brainly.com/question/9509278

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3 0
2 years ago
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-
Alchen [17]

Answer:

T₂  = 84.375 K

Explanation:

Given data:

Initial volume = 3.3 L

Initial pressure = 2000 torr

Initial temperature = 225 K

Final temperature = ?

Final volume = 2.75 L

Final pressure = 900 torr

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

T₂  = P₂V₂ T₁ /P₁V₁

T₂  = 900 torr× 2.75 L× 225 K / 2000 torr×3.3 L

T₂  = 556875 K/ 6600

T₂  = 84.375 K

7 0
3 years ago
Two reactants, each having a mass of 50.0 g, react fully in a beaker. What is the total mass of the products in the reaction?
krok68 [10]

Answer:

100g......sieiekeskslapaokdkz

6 0
2 years ago
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