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kap26 [50]
2 years ago
8

How much momentum does a 200 kg rhino have that is running at 35 m/s E

Chemistry
2 answers:
nirvana33 [79]2 years ago
5 0

Answer:

7000 kg*m/s E

Explanation:

Momentum formula: p=mv

m=200kg

v=35 m/s East

p=(200kg)(35m/s E)

m=7000 kg*m/s E

If you want to simplify it further, m=7*10^3 kg*m/s E

AlexFokin [52]2 years ago
4 0

Answer:

\boxed {\boxed {\sf 7000 \ kg*m/s \ E}}

Explanation:

Momentum is the product of mass and velocity.

p=m*v

The mass is 200 kilograms and the velocity is 35 meters per second east.

m= 200 \ kg \\v= 35 \ m/s \ E

Substitute the values into the formula.

p= 200 \ kg * 35 \ m/s \ E

Multiply.

p= 7000 \ kg * m/s \ E

The rhino has 7000 kg*m/s E of momentum.

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The change of phase from a vapor to a liquid is called _____. evaporation condensation distillation vaporization
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Why is the use of inquiry process a practical way to approach science?
just olya [345]

Answer:

Explanation:

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3 years ago
Express 14.80 × 12.10 × 5.05 in scientific notation with the proper significant figures.
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A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spheric
Luba_88 [7]

Complete Question

A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 74.0 wide. The biologist estimates she will need 2600 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to significant digits.

Answer:

The pressure required is P_2= 12.2 \ atm

Explanation:

Generally the volume of a sphere is mathematically denoted as

             V_s = \frac{4}{3} * \pi r^3

Substituting r =  \frac{d}{2} = \frac{74}{2} = 37cm

          V_s = \frac{4}{3} * 3.42 * (37)^2

               V_s = 2.121746 *10^5 cm^3

Converting to Liters

               V_s = \frac{2.121746 *10^5}{1000}

                V_s= 212.1746L

Assume that the pressure at which the air is given to the diver is 1 atm when the air was occupying a volume of 2600L

So

From Charles law

               P_1V_1 = P_2 V_s

Substituting  V_1 =2600 L ,   P_1 = 1 atm , V_s  =212.1746L , and making P_2 the subject we have

                 P_2 = \frac{P_1 * V_1}{V_s}

                     = \frac{1 * 2600}{212.1746}

                    P_2= 12.2 atm

               

6 0
3 years ago
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