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Irina18 [472]
3 years ago
7

Alveolar air (a mixture of nitrogen, oxygen, and carbon dioxide) has a total pressure of 0.998 atm. If the partial pressure of o

xygen gas is 0.198 atm and the partial pressure of nitrogen gas is 0.770 atm, what is the partial pressure of carbon dioxide in millimeters of mercury?
Chemistry
1 answer:
Vadim26 [7]3 years ago
3 0

Answer:

22.8 mmHg

Explanation:

According to Dalton's law of partial pressures, the total pressure of a mixture of gases is obtained as the sum of the partial pressures if all the individual gases present in the mixture.

Since the total pressure of gases in the mixture is 0.998 atm, the partial pressure of carbon dioxide is;

PCO2 = [Ptotal - (PO2+ PN2)]

Hence;

PCO2 = [0.998 - (0.198 + 0.770)]

PCO2 = 0.03

Since

1 atm = 760 mmHg

0.03 atm = 0.03 × 760 /1

=22.8 mmHg

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If the valency of oxygen is 2, derive the valencies of the other elements present in the following oxides. Na2O, ZnO , Al2O3 , M
11Alexandr11 [23.1K]

Answer:

1)Na2O

let the valency of Na is x

2(x)+(2)=0

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7 0
3 years ago
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How many moles of Carbon are in 3.06 g of Carbon
natta225 [31]

Answer:

\boxed {\boxed {\sf 0.255 \ mol \ C }}

Explanation:

If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

Look up the molar mass of carbon.

  • Carbon (C): 12.011 g/mol

Set up a ratio using the molar mass.

\frac {12.011 \ g \ C}{ 1 \ mol \ C}

Since we are converting 3.06 grams to moles, we multiply by that value.

3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}

Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.

3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}                      

3.06 * \frac{1 \ mol \ C}{12.011 }    

\frac {3.06}{12.011 } \ mol \ C                                

0.25476646 \ mol \ C

The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

  • 0.25476646

The 7 in the ten-thousandth place tells us to round the 4 up to a 5.

0.255 \ mol \ C

3.06 grams of carbon is approximately <u>0.255 moles of carbon.</u>

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denis23 [38]
C. The mass number is the amount of Protons and electrons there are combined, so 200 - 80 is 120.
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