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Irina18 [472]
3 years ago
7

Alveolar air (a mixture of nitrogen, oxygen, and carbon dioxide) has a total pressure of 0.998 atm. If the partial pressure of o

xygen gas is 0.198 atm and the partial pressure of nitrogen gas is 0.770 atm, what is the partial pressure of carbon dioxide in millimeters of mercury?
Chemistry
1 answer:
Vadim26 [7]3 years ago
3 0

Answer:

22.8 mmHg

Explanation:

According to Dalton's law of partial pressures, the total pressure of a mixture of gases is obtained as the sum of the partial pressures if all the individual gases present in the mixture.

Since the total pressure of gases in the mixture is 0.998 atm, the partial pressure of carbon dioxide is;

PCO2 = [Ptotal - (PO2+ PN2)]

Hence;

PCO2 = [0.998 - (0.198 + 0.770)]

PCO2 = 0.03

Since

1 atm = 760 mmHg

0.03 atm = 0.03 × 760 /1

=22.8 mmHg

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Fluorine

Explanation:

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How many grams is 20 moles of (nh4)2so4 please show work
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3 0
3 years ago
If you have 10 grams of Lithium Oxide what will the volume be? Show your work
gogolik [260]

Answer:

Volume occupied by 10 grams of Lithium Oxide at STP is 7.52 L

Explanation:

STP (Standard Temperature and Pressure) : It is used while performing calculation on gases and provide standards of measurements while performing experiment.

According to IUPAC (International Union of Pure And applied Chemistry) , standard temperature is 273.15 K and Pressure is 100 kPa (0.9869 atm). At STP condition 1 mole of substance occupies 22.4 L volume .

Molar mass of Lithium Oxide = 29.8 g/mol

Li_{2}O = 2(6.9) + 15.99 = 29.8

Mass of 1 mole Li_{2}O = 29.8 g

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29.8 g Li_{2}O occupies, V = 22.4 L

1 g Li_{2}O occupies ,V = \frac{22.4}{29.8}

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3 years ago
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