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7nadin3 [17]
4 years ago
9

What is the oxidation number of manganese (Mn) in potassium permanganate (KMnO4)? (3 points)

Chemistry
1 answer:
monitta4 years ago
7 0
K(+1)
Mn(x)
O(-2)
1+x-2*4=0
x=7
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Answer:

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q=c\times \Delta T

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Now put all the given values in the above formula, we get:

q=2.68 kJ/^oC\times 3.08^oC

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\Delta H_{comb}=-\frac{q}{n}

where,

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n = number of moles methane = \frac{\text{Mass of methane}}{\text{Molar mass of methane }}=\frac{2.00 g}{16.042 g/mol}=0.1247 mole

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