Answer:
The approximate molar enthalpy of combustion of this substance is -66 kJ/mole.
Explanation:
First we have to calculate the heat gained by the calorimeter.

where,
q = Heat gained = ?
c = Specific heat = 
ΔT = The change in temperature = 3.08°C
Now put all the given values in the above formula, we get:


Now we have to calculate molar enthalpy of combustion of this substance :

where,
= enthalpy change = ?
q = heat gained = 8.2544kJ
n = number of moles methane = 

Therefore, the approximate molar enthalpy of combustion of this substance is -66 kJ/mole.
Answer:idk
Explanation:of a 0.26 M triethylamine, (C2H5)3N, solution. ... 5. Predict if a decrease in temperature is favorable for the following reactions: (5 pts) a. H2O(s)
Answer:
Erosion/Weathering
Explanation:
Because the rock is exposed to the ocean, the constant push and pull of the water against the rock erodes the material away and moves it elsewhere. The wind likely aided in this process as well. This caused the big gap in the center of the rock.