Question

Answer fast my H.W is hard

Answer 1

Answer: The molality of $MgF_2$ solution is 4.013 m

Explanation:

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg.

The formula used to calculate molarity:

     .....(1)

Given values:

Given mass of $MgF_2$ = 20.0 g

Molar mass of = 62.3 g/mol

Mass of solvent = 80.0 g

Putting values in equation 1, we get:

$\text{Molality of }MgF_2=\frac{20.0\times 1000}{62.3\times 80.0}\\\\\text{Molality of }MgF_2=4.013m$

Hence, the molality of $MgF_2$ solution is 4.013 m