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Lana71 [14]
3 years ago
10

T/F. When a molecule contains three bonds and a single lone pair attached to the central atom, the molecular geometry is trigona

l planar.
Chemistry
1 answer:
lesantik [10]3 years ago
7 0

Answer:

False

Explanation:

In chemistry, trigonal planar is a molecular geometry model with one atom at the center and three atoms at the corners of an equilateral triangle, called peripheral atoms, all in one plane. In an ideal trigonal planar species, all three ligands are identical and all bond angles are 120°.

Meaning there shouldn't be any lone pair.

Look up "Structure of a trigonal planar molecule" for a visual

So it is false.

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Suppose you mix one mole of sulfuric acid (H2SO4) with 1 mole of sodium hydroxide(NaOH).
olasank [31]

Answer & Explanation:

  • The neutralization of H₂SO₄ with NaOH is occurred according to the balanced equation:

<em>H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O,</em>

It is clear that every 1.0 mol of H₂SO₄ needs 2 mol of NaOH to be neutralized completely.

<em>So, when you mix one mole of sulfuric acid with 1 mole of sodium hydroxide, there will be an excess of sulfuric acid.</em>

<em>Thus, the pH of the solution remain below 7.</em>

7 0
3 years ago
Please help, I really don’t understand this!!!
kap26 [50]

<u>Analysing the Question:</u>

We are given the balanced equation:

C₆H₁₂O₆ + 6O₂→ 6CO₂ + 6H₂O

from this equation, we can say that: <em>for every 1 mole of Glucose, we need 6 moles of Oxygen</em>

<u>Moles of Glucose used in the reaction:</u>

Molar mass of Glucose = 180 grams / mol

Given mass of Glucose = 1 gram

Mole of Glucose = Given mass / Molar mass

Moles of Glucose = 1 / 180 moles

<u>Mass of Oxygen required:</u>

We know that for every mole of Glucose, we need 6 moles of Oxygen

So, for 1/180 moles of Glucose, we need 6 / 180 = 1 / 30 moles of Oxygen

Mass of 1 / 30 moles of Oxygen:

Mass = Molar mass * number of moles

Mass of Oxygen = 32 * 1/30

Mass of Oxygen  = 32 / 30

Mass of Oxygen = 1.06 grams

5 0
3 years ago
If the mass of the object below is 28g, what is the density of the object below. Units are in cm below. Please round your answer
Murljashka [212]

Answer:

d = 0.93 g/cm³

Explanation:

Given data:

Mass of object = 28 g

Volume of object = 3cm×2cm×5cm

density of object = ?

Solution:

Volume of object = 3cm × 2cm ×5cm

Volume of object = 30 cm³

Density of object:

d = m/v

by putting values,

d = 28 g/ 30 cm³

d = 0.93 g/cm³

3 0
3 years ago
During photosynthesis the chemical bonds between are broken
Vaselesa [24]

Answer:

yes they are broken down into smaller units

5 0
3 years ago
What mass of Ca(NO3)2 is equal to 0.75 moles of this substance?
sattari [20]

Answer:

Ca - 63.546 g

2N - 28.014 g

2O3 - 96 g

Ca(NO3)2 = 187.56 g

187.56 g x 0.75 mol = 140.67 g

Explanation:

Hope this helps

5 0
3 years ago
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