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2 years ago

What is the pressure in a 27.0-L cylinder filled with 44.9 g of oxygen gas at a temperature of 315 KK

Chemistry

1 answer:

steposvetlana [31]2 years ago

6 0

Answer:

1.343 atm

Explanation:

We are given the following;

Pressure, p = ?

Volume v = 27 L

Mass of oxygen = 44.9 g

Temperature, T = 315 K

The formular relating all these variables is the equation;

PV = nRT

where R = gas constant = 0.08206 L atm / mole K

To obtain n, we use;

number of moles, n = Mass / molar mass = 44.9 / 32 = 1.403 moles

From the ideal gas equation;

P = nRT / V

P = 1.403 * 0.08206 * 315 / 27

P = 36.27 / 27 = 1.343 atm

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What is a process of reacting an acid with a base until an equivalence point is reached

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3 years ago

A gas at 1.2 atm has a

Papessa [141]

Answer:

1.26 mole

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3 years ago

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finlep [7]

Answer:

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3.120 mol Si * $\frac{1molMg_3(Si_2O_5)_2(OH)_2}{4molSi}$ = 0.78 mol Mg₃(Si₂O₅)₂(OH)₂

Then we can convert Mg₃(Si₂O₅)₂(OH)₂ moles into hydrogen moles, keeping in mind that there are 2 hydrogen moles per Mg₃(Si₂O₅)₂(OH)₂ mol:

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3 years ago

The substances below are listed by increasing specific heat capacity value. Starting at 30.0 °C, they each absorb 100 kJ of ther

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Answer:

Silver, 0.239 J/(g °C)

Explanation:

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Heat change = mass of substance × specific heat × change in temperature

Therefore; considering same amount of substance or equal masses and have the same initial temperature.

The change in temperature will be inversely proportional to the specific heat.
Therefore; the higher the specific heat lower the temperature change.
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Therefore; the one that will increase in temperature the most is Silver

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3 years ago