Question

The pressure of a gas is 100.0 kPa and its volume is 500.0 mL. If the volume increases to 1,000.0 mL, what is the new pressure of the gas?

Answer 1

Answer:

$P_2=50kPa$

Explanation:

Hello,

In this case, we can apply the Boyle's law in order to understand the pressure-volume relationship as an inversely proportional relationship relating the initial and the final volume:

$P_1V_1=P_2V_2$

Next, we compute the final pressure P2:

$P_2=\frac{P_1V_1}{V_2}=\frac{100.00kPa*500.0mL}{1000.0mL} \\\\P_2=50kPa$

Thus we validate, the higher the volume the lower the pressure.

Best regards.