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Sauron [17]
3 years ago
8

A certain compound is made up of three chlorine atoms, one phosphorus atom, and one oxygen atom. What is the chemical formula of

this compound
Chemistry
1 answer:
enyata [817]3 years ago
6 0

Answer:

POCl3

Explanation:

A compound is a substance made up of atoms of different elements. The number of atoms each element posseses make up the chemical formula of the compound. In this question, a certain compound is made up of three chlorine atoms (Cl3), one phosphorus atom (P), and one oxygen atom (O).

Combining these atoms of different quantity together, this means that the compound will have a chemical formula: POCl3. This compound is called phosphorus oxychloride.

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3 years ago
Wat two common uses for Gallium??
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mirrors and metal thermometers

Explanation:

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. How many grams of Na2SO4 are required to make 2700 mL of a 2.0 M solution?
ratelena [41]

Answer:

Explanation:

From the net ionic equation

Ba2+(aq) + SO42-(aq) ==> BaSO4(s) we see that 1 mole Ba2+ reacts with 1 mole SO42- to -> 1 mol BaSO4

Find moles of Ba2+ used: 0.250 moles/L x 0.0323 L = 0.008075 moles Ba2+

Find moles SO42- present: 0.008075 moles Ba2+ x 1 mol SO42-/1 mol Ba2+ = 0.008075 mol SO42-

Find mass of Na2SO4 present: 0.008075 mol SO42- x 1 mol Na2SO4/1 mol SO42- x 142.04 Na2SO4/mole = 1.14698 g = 1.15 g Na2SO4 (to 3 significant figures)

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Calculate the amount of energy , in Joules, required to raise the temperature of 15.5 g of liquid water from 0.00o C to 75.0 oC.
deff fn [24]

Answer:

10043.225 J

Explanation:

We'll begin by calculating the amount of heat needed to change ice to water since water at 0°C is ice. This is illustrated below:

Mass (m) = 15.5g

Latent heat of fussion of water (L) = 334J/g

Heat (Q1) =..?

Q1 = mL

Q1 = 15.5 x 334

Q1 = 5177 J

Next, we shall calculate the amount of heat needed to raise the temperature of water from 0°C to 75°C.

This is illustrated below:

Mass = 15.5g

Initial temperature (T1) = 0°C

Final temperature (T2) = 75°C

Change in temperature (ΔT) = T2 – T1 = 75 – 0 = 75°C

Specific heat capacity (C) of water = 4.186J/g°C

Heat (Q2) =?

Q2 = MCΔT

Q2 = 15.5 x 4.186 x 75

Q2 = 4866.225 J

The overall heat energy needed is given by:

QT = Q1 + Q2

QT = 5177 + 4866.225

QT = 10043.225 J

Therefore, the amount of energy required is 10043.225 J

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