Answer:
the initial velocity of the ball is 17.14 m/s
Explanation:
Given;
maximum height reached by the ball, h = 15 m
let the initial velocity of the ball = u
at maximum height, the final velocity of the ball is zero, v = 0
The initial velocity of the ball is calculated by using the following upward motion kinematic equation;
v² = u² - 2gh
0 = u² - 2(9.8 x 15)
u² = 294
u = √294
u = 17.14 m/s
Therefore, the initial velocity of the ball is 17.14 m/s
Answer:
Step-by-step explanation:
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Answer:
The box displacement after 6 seconds is 66 meters.
Explanation:
Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (
), in meters, can be determined by the following expression:
(1)
Where:
- Initial velocity, in meters per second.
- Time, in seconds.
- Acceleration, in meters per square second.
If we know that 
, 
and 
, then the box displacement after 6 seconds is:
The box displacement after 6 seconds is 66 meters.
