When you see a quantity like 20 m/s N, how do you know that it's a vector quantity and not a scalar quantity?

Physics

1 answer:

KengaRu [80]2 years ago

5 0

We know that 20 m/s N is a vector quantity because N in the expression signifies the direction

<h3>What is a vector quantity?</h3>

This is a which have both magnitude and direction. Example include:

Velocity
Displacement
Force
Acceleration
Moment
Weight

<h3>How to determine whether 20 m/s N is a vector quantity</h3>

20 m/s indicates just the speed i.e magnitude
20 m/s N indicates the speed i.e magnitude why the N indicates the direction.

Thus, we can conclude that 20 m/s N is a vector quantity because it has both magnitude and direction.

Learn more about scalar and vector quantity:

brainly.com/question/774036

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Based on Newton's law of motion, which combination of rocket bodies and engine will result in the acceleration of 40 m/s ^2 at t

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The question is incomplete. The complete question is :

The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.

A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.

Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?

Body 3 + Engine 1

Body 2 + Engine 2

Body 1 + Engine 2

Body 1 + Engine 1

Solution :

Given :

Body Mass (gram) Engine Force (newtons)

1 500 1 25

2 1500 2 20

3 750 3 30

The body 1 has a mass of 500 gram which is equal to 0.5 kg

And engine 2 has a force of 20 newtons.

We know that according to Newton's laws of motion,

Force = mass x acceleration

20 = 0.5 x acceleration

Acceleration $=\frac{20}{0.5}$

$=\frac{200}{5}$

$= 40 \ m/s^2$

Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of $40 \ m/s^2$ at the start of the launch.