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Reika [66]
2 years ago
15

When you see a quantity like 20 m/s N, how do you know that it's a vector quantity and not a scalar quantity?

Physics
1 answer:
KengaRu [80]2 years ago
5 0

We know that 20 m/s N is a vector quantity because N in the expression signifies the direction

<h3>What is a vector quantity?</h3>

This is a which have both magnitude and direction. Example include:

  • Velocity
  • Displacement
  • Force
  • Acceleration
  • Moment
  • Weight

<h3>How to determine whether 20 m/s N is a vector quantity</h3>
  • 20 m/s indicates just the speed i.e magnitude
  • 20 m/s N indicates the speed i.e magnitude why the N indicates the direction.

Thus, we can conclude that 20 m/s N is a vector quantity because it has both magnitude and direction.

Learn more about scalar and vector quantity:

brainly.com/question/774036

#SPJ12

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I think the answer is "A roller coaster going up a hill"

Explanation:

Because the roller coaster is losing kinetic and losing potential enregy.

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Why is physics an important part of history
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History and physics are intertwined through all the revolutionary thinkers, scientists, and people who studied these ideas. For example, many historical thinkers such as Isaac Newton and Galileo Galilei not only had revolutionary ideas, but they also changed life forever as the people knew it. It shocked the people and taught them new things, and upset the church.

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A car starts with an initial speed of 12 m/s and accelerates at 3 m/s/s for 5 seconds
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Explanation:

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a = 3 m/s^2

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3 years ago
Which of the following are not properties of metals? Check all that apply. *
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3 years ago
Metal sphere 1 has a positive charge of 7.00 nc . metal sphere 2, which is twice the diameter of sphere 1, is initially uncharge
MariettaO [177]

Answer:

2.33 nC, 4.67 nC

Explanation:

when the two spheres are connected through the wire, the total charge (Q=7.00 nC) re-distribute to the two sphere in such a way that the two spheres are at same potential:

V_1 = V_2 (1)

Keeping in mind the relationship between charge, voltage and capacitance:

C=\frac{Q}{V}

we can re-write (1) as

\frac{Q_1}{C_1}=\frac{Q_2}{C_2} (2)

where:

Q1, Q2 are the charges on the two spheres

C1, C2 are the capacitances of the two spheres

The capacitance of a sphere is given by

C=4 \pi \epsilon_0 R

where R is the radius of the sphere. Substituting this into (2), we find

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 R_2} (3)

we also know that sphere 2 has twice the diameter of sphere 1, so the radius of sphere 2 is twice the radius of sphere 1:

R_2 = 2R_1

So the eq.(3) becomes

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 2R_1}

And re-arranging it we find:

Q_2 = 2Q_1

And since we know that the total charge is

Q_1 + Q_2 = 7.00 nC

we find

Q_1 = 2.33 nC\\Q_2 = 4.67 nC

3 0
3 years ago
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