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3 years ago

A 100 Kg man is diving off a 50 meter cliff. What is his kinetic energy when he is 20 meters from the water?

Physics

1 answer:

iren2701 [21]3 years ago

8 0

Answer:

$K.E=29.403125J$

Explanation:

From the question we are told that

Mass $M=100$

Height $50-20=30m$

Generally the equation for velocity before impact is is is mathematically given by

$v=\sqrt{2gh}$

$v=\sqrt{2*9.8*30}$

$v=24.25$

Generally the equation for Kinetic Energy is is mathematically given by

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}*100*(24.25)^2\\$

$K.E=29403.125J$

$K.E=29.403125J$

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3 years ago

Evidence supports the idea that increases in carbon dioxide and methane in Earth's atmosphere are major contributors to global w

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2 years ago

The body falls in a free fall 11s.Calculate: a) from what height the body of the paddle) what path did it fall during the last s

JulsSmile [24]

Answer:

a) h = 593.50 m

b) h₁₁ = 103 m

c) vf = 107.91 m/s

Explanation:

We will use second equation of motion to find the height:

$h = v_{i}t + (\frac{1}{2})gt^2$

where,

h = height = ?

vi = initial speed = 0 m/s

t = time taken = 11 s

g = 9.81 /s²

Therefore,

$h = (0\ m/s)(11\ s) + (\frac{1}{2})(9.8\ m/s^2)(11\ s)^2\\\\$

h = 593.50 m

For the distance travelled in last second, we first need to find velocity at 10th second by using first equation of motion:

$v_{f} = v_{i} + gt$

where,

vf = final velocity at tenth second = v₁₀ = ?

t = 10 s

vi = 0 m/s

Therefore,

$v_{10} = 0\ m/s + (9.81\ m/s^2)(10\ s)\\\\v_{10} = 98.1\ m/s$

Now, we use the 2nd equation of motion between 10 and 11 seconds to find the height covered during last second:

$h = v_{i}t + (\frac{1}{2})gt^2$

where,

h = height covered during last second = h₁₁ = ?

vi = v₁₀ = 98.1 m/s

t = 1 s

Therefore,

$h_{11} = (98.1\ m/s)(1\ s) + (\frac{1}{2})(9.8\ m/s^2)(1\ s)^2\\\\$

h₁₁ = 103 m

Now, we use first equation of motion for complete motion:

$v_{f} = v_{i} + gt$

where,

vf = final velocity at tenth second = ?

t = 11 s

vi = 0 m/s

Therefore,

$v_{f} = 0\ m/s + (9.81\ m/s^2)(11\ s)$

vf = 107.91 m/s

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3 years ago