It is often revealed <span>at the resolution of the story, when the reader can see how the story ends.</span>
Answer:
The maximum power density in the reactor is 37.562 KW/L.
Explanation:
Given that,
Height = 10 ft = 3.048 m
Diameter = 10 ft = 3.048 m
Flux = 1.5
Power = 835 MW
We need to calculate the volume of cylinder
Using formula of volume

Put the value into the formula


We need to calculate the maximum power density in the reactor
Using formula of power density

Where, P = power density
E = energy
V = volume
Put the value into the formula


Hence, The maximum power density in the reactor is 37.562 KW/L.
Answer:
hellooooo :) ur ans is 33.5 m/s
At time t, the displacement is h/2:
Δy = v₀ t + ½ at²
h/2 = 0 + ½ gt²
h = gt²
At time t+1, the displacement is h.
Δy = v₀ t + ½ at²
h = 0 + ½ g (t + 1)²
h = ½ g (t + 1)²
Set equal and solve for t:
gt² = ½ g (t + 1)²
2t² = (t + 1)²
2t² = t² + 2t + 1
t² − 2t = 1
t² − 2t + 1 = 2
(t − 1)² = 2
t − 1 = ±√2
t = 1 ± √2
Since t > 0, t = 1 + √2. So t+1 = 2 + √2.
At that time, the speed is:
v = at + v₀
v = g (2 + √2) + 0
v = g (2 + √2)
If g = 9.8 m/s², v = 33.5 m/s.
Answer:
my name is Deepika Pandey anion I am 9 years old my father name is Dinesh Pandey my name is and my sister name is sister name is a
Answer:
(a) 0.345 T
(b) 0.389 T
Solution:
As per the question:
Hall emf, 
Magnetic Field, B = 0.10 T
Hall emf, 
Now,
Drift velocity, 

Now, the expression for the electric field is given by:
(1)
And

Thus eqn (1) becomes
where
d = distance
(2)
(a) When 

(b) When 
