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Delicious77 [7]
3 years ago
11

Spring is here, and Cho and her uncle would like to go fishing for the weekend in Washington. Cho could either go to the river i

n town where anyone can fish without a permit, or she could drive up to a stream located on her family's property in the countryside to fish. Assume that, no matter where people fish, all of the fish that are caught would be kept (that is, there is no "catch and release" policy).
The fish in the private stream are considered(Rival in consumption/ nonrival in consumption) and (Excludable/ nonexcludable) whereas the fish in the river are(Rival in consumption/ nonrival in consumption) and (Excludable/ nonexcludable) . In other words, the fish in the private stream are an example of (A public good/ private good/ club good/ common resource) , and the fish in the river are an example of (A public good/ private good/ club good/ common resource). Fishing in the river will likely lead to( Tragedy of the commons/ adverse selection / the free-rider problem) because of which of the following reasons?

A. Nobody will enjoy fishing because of the lack of private contributions to the maintenance of the river.

B. Anyone can fish in the river, and one person's fishing activity decreases the ability of someone else to fish with success.

C.All fishermen will choose to fish in the river because of the limited access to the stream.

D, All fishermen will choose to fish in the stream believing that there are more fish there.
Physics
1 answer:
aleksley [76]3 years ago
8 0

Answer:

B. True  since when a person removes the weights there is less for the other people

Explanation:

This problem ask us consider some things

In the private current it is considered a good example of a private good

the fish in the river are a common resource

the fishing in the river is tragedy of the commons

A False. The fish in the river are natural and not sown

B. True  since when a person removes the weights there is less for the other people

C. False. Some fishermen will go to the creek

D. False some will go to the river

.

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ozzi
The answer to your question is Metal
8 0
3 years ago
A bowling ball moving with a velocity of 5V to the right collides elastically with a beach ball moving at a velocity 2V to the l
katen-ka-za [31]

Answer:

v'_2=3V

Explanation:

From the question we are told that:

Bowling ball Speed v_1=5 m/s

Beach ball Speed v_2=2 m/s

Let The Mass be equal i.e

 M_1=M_2

Therefore

Generally the equation for Velocity of beach ball after collision v'_2 is mathematically given by

Since Velocity is Vector Quantity

Therefore

 v'_2=v_1-v_2

 v'_2=5-2

 v'_2=3V

3 0
3 years ago
Ali mixes 20g of Sodium Chloride in 100g of water at 15 Degree °C. Calculate the mass of the solution
Lera25 [3.4K]

Answer:

The mass of the solution is 120 g.

Explanation:

The mass of the solution is given by:

m_{sol} = m_{1} + m_{2}

Where:

m_{sol}: is the mass of the solution

m_{1}: is the mass of the solvent

m_{2}: is the mass of the solute

In the solution, the solvent is the majority compound (in mass) and the solute is the minority (in mass), so the solvent is the water and the solute is sodium chloride.          

Hence, the mass of the solution is:

m_{sol} = m_{1} + m_{2} = 100 g + 20 g = 120 g  

I hope it helps you!                  

7 0
3 years ago
The​ half-life of a certain radioactive substance is 12 hours. There are 19 grams present initially. a. Express the amount of su
neonofarm [45]

Answer:

(a) N=19\times e^{-\lambda t}

(b) 15 hours

Explanation:

half life, T = 12 hours

No = 19 g

(a) Let N be the amount remaining after time t.

Let λ be the decay constant.

\lambda =\frac {0.6931}{T}

The equation of radioactivity used here is given by

N=N_{o}e^{-\lambda t}

N=19\times e^{-\lambda t}

(b) N = 8 gram

Substitute the values in above equation

\lambda =\frac {0.6931}{12}

λ = 0.0577 per hour

So, 8=19\times e^{-0.577t}

e^{-0.0577t}=0.421

Take natural log on both the sides

- 0.0577 t = - 0.865

t = 15 hours

4 0
3 years ago
An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
umka21 [38]

Answer:

Explanation:

s = s₀ + v₀t + ½at²

s = 0 + 0(15) + ½(6)(15²)

s = 675 m

Not sure what the free fall acceleration is needed for, but if the object is dropped from a high enough point, it will travel in 15 seconds

s = ½10(15²) = 2250 m  if air resistance is ignored

7 0
3 years ago
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