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Delicious77 [7]
3 years ago
11

Spring is here, and Cho and her uncle would like to go fishing for the weekend in Washington. Cho could either go to the river i

n town where anyone can fish without a permit, or she could drive up to a stream located on her family's property in the countryside to fish. Assume that, no matter where people fish, all of the fish that are caught would be kept (that is, there is no "catch and release" policy).
The fish in the private stream are considered(Rival in consumption/ nonrival in consumption) and (Excludable/ nonexcludable) whereas the fish in the river are(Rival in consumption/ nonrival in consumption) and (Excludable/ nonexcludable) . In other words, the fish in the private stream are an example of (A public good/ private good/ club good/ common resource) , and the fish in the river are an example of (A public good/ private good/ club good/ common resource). Fishing in the river will likely lead to( Tragedy of the commons/ adverse selection / the free-rider problem) because of which of the following reasons?

A. Nobody will enjoy fishing because of the lack of private contributions to the maintenance of the river.

B. Anyone can fish in the river, and one person's fishing activity decreases the ability of someone else to fish with success.

C.All fishermen will choose to fish in the river because of the limited access to the stream.

D, All fishermen will choose to fish in the stream believing that there are more fish there.
Physics
1 answer:
aleksley [76]3 years ago
8 0

Answer:

B. True  since when a person removes the weights there is less for the other people

Explanation:

This problem ask us consider some things

In the private current it is considered a good example of a private good

the fish in the river are a common resource

the fishing in the river is tragedy of the commons

A False. The fish in the river are natural and not sown

B. True  since when a person removes the weights there is less for the other people

C. False. Some fishermen will go to the creek

D. False some will go to the river

.

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Technician A says a that a voltmeter can be used to monitor the output signal of an optical sensor. Technician B says that optic
katrin2010 [14]

Answer:

B. Technician B only

Explanation:

An oscilloscope can be used to check the output signal of an optical sensor. The oscilloscope has the functioning of viewing the results in the form of waveform and its time scale settings can be altered to meet the requirements of the results.

A voltmeter cannot be <u>directly</u> used to monitor the output signal of an optical sensor. But a <u>digital multi-meter</u> can be used to check an optical sensor if the digital multi-meter is set on AC - Volt reading mode.

5 0
2 years ago
An air-track glider attached to a spring oscillates between the 10 cm mark and the 60 cm mark on the track. The glider completes
Assoli18 [71]

Answer:

a) Time period is 3.3 seconds

b) The frequency is 0.3030 Hz

c) amplitude is 0.25 m

d) maximum speed is 0.476 m/s

Explanation:

Given the data in the question;

a) Period

Time Period T = Time taken for one oscillation

T = 33s / 10 = 3.3 seconds

Therefore, Time period is 3.3 seconds

b) Frequency

we know that frequency is the inverse of time period

so;

Frequency f = 1/T = 1 / 3.3 s

Frequency f = 0.3030 Hz

Therefore, The frequency is 0.3030 Hz

c) amplitude

amplitude A = \frac{1}{2}( 60 cm - 10 cm )

A = \frac{1}{2} × 50 cm

A = 25 cm

A = 0.25 m

Therefore, amplitude is 0.25 m

d) maximum speed of the glider

maximum speed V_{max} = ωA

and ω = 2π/T

so maximum speed V_{max} = \frac{2\pi }{T}A

so we substitute

so maximum speed V_{max} = \frac{2\pi }{3.3} × 0.25 m

so maximum speed V_{max} = 0.476 m/s

Therefore, maximum speed is 0.476 m/s

5 0
2 years ago
An object moving at a velocity of 32 m/s slows to a stop in 4 seconds. What was its acceleration
Leya [2.2K]

Answer:

8

Explanation:

Because you divide 32/4 which gives you 8.

6 0
3 years ago
Silver has a mass of 10.5 grams and a volume of 19.3 cm3. What is its density?
Neko [114]

Answer:

<h3>The answer is 0.54 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{10.5}{19.3}  \\  = 0.54404145...

We have the final answer as

<h3>0.54 g/cm³</h3>

Hope this helps you

7 0
3 years ago
A sonar emits a sound signal of frequency 40000Hz, towards the bottom of the sea.
kap26 [50]

Answer:

0.000025s

Explanation:

Period it’s. : T(s)= 1/f(Hz)=1/40000Hz=0.000025s

8 0
2 years ago
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