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3 years ago

Who was the first scientist to propose that an object could emit only certain amounts of energy?

Physics

1 answer:

Rzqust [24]3 years ago

3 0

It was Niels Bohr who proposed it

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Two loudspeakers emit sound waves along the x-axis. A listener in front of both speakers hears a maximum sound intensity when sp

yKpoI14uk [10]

Answer

given,

difference between the two consecutive maximum

λ = 0.870 - 0.540

λ = 0.33 m

speed of sound = 340 m/s

b) frequency of the sound

v = f x λ

340 = f x 0.33

$f =\dfrac{340}{0.33}$

f = 1030.3 Hz

a) phase difference

the expression of phase difference is given by

$\phi = \dfrac{2\pi}{\lambda}\ \delta$

$\delta = \Delta x - \lambda$

$\delta = 0.540 - 0.33$

$\delta = 0.21\ m$

now,

$\phi = \dfrac{2\pi}{\lambda}\ \times 0.21$

$\phi = \dfrac{2\pi}{0.33}\ \times 0.21$

$\phi = 3.99 rad$

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3 years ago

Which statement represents a healthy choice for a pregnant woman? A mother eats twice as much to support her growing fetus. A mo

max2010maxim [7]

Answer:

A mother with gestational diabetes decides to limit her sugar intake.

Explanation:

7 0

3 years ago

Read 2 more answers

A circuit contains two resistors in series. The voltage drop across the first is 10 V. The voltage drop across the second is als

Norma-Jean [14]

Hi there!

Voltage in a series can be expressed by the following:

$V_T = V_1 + V_2$

In words, the total voltage is equal to the sum of the individual voltage drops in a SERIES circuit.

We can solve for the total voltage:

$V_T = 10 + 10 = \boxed{\text{ D. 20 V}}$

6 0

2 years ago

PLEASEEEE HELPPPPPPPPPPPP

lesantik [10]

Answer:

240 meter

Explanation:

d= s*d=60m/s * 4sec=240 meter

7 0

3 years ago

a lorry travels 3600m on a test track accelerating constantly at 3m/s squared from standstill. what is the final velocity (3 sig

suter [353]

The final velocity of the truck is found as 146.969 m/s.

Explanation:

As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.

Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.

$2as =v^{2} - u^{2} \\\\v^{2} = 2as + u^{2}$

Then, the final velocity will be

$v^{2} = 2 * 3 * 3600 + 0 = 21600\\ \\v=\sqrt{21600}=146.969 m/s$

Thus, the final velocity of the truck is found as 146.969 m/s.

8 0

3 years ago