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lozanna [386]
3 years ago
5

Who was the first scientist to propose that an object could emit only certain amounts of energy?

Physics
1 answer:
Rzqust [24]3 years ago
3 0
It was Niels Bohr who proposed it
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give an example of situation in which an automobile driver can have a centripetal acceleration but no tangential speed
Mars2501 [29]

There is no need for tangential acceleration when moving in a circle at a constant speed.

<h3>What is centripetal acceleration?</h3>

centripetal acceleration refers to the speed at which a body moves through a circle. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude, the speed, and a direction), when a body travels in a circle, its direction is constantly changing, which causes a change in velocity, which results in an acceleration.

<h3>Which is an example of centripetal acceleration?</h3>

Centripetal acceleration occurs when you spin a ball on a string above your head. A car experiences centripetal acceleration when it is being driven in a circle. Additionally, a satellite in orbit around the Earth experiences centripetal acceleration.

To know more about tangential acceleration :

brainly.com/question/14993737

#SPJ9

6 0
1 year ago
A rocket is fired at 100 m/s at an angle of 37, how many seconds did it take to get to the top?
Kobotan [32]

Answer:

6.14 s

Explanation:

The time the rocket takes to reach the top is only determined from its vertical motion.

The initial vertical velocity of the rocket is:

u_y = u sin \theta = (100)(sin 37^{\circ})=60.2 m/s

where

u = 100 m/s is the initial speed

\theta=37^{\circ} is the angle of launch

Now we can apply the suvat equation for an object in free-fall:

v_y = u_y +gt

where

v_y is the vertical velocity at time t

g=-9.8 m/s^2 is the acceleration of gravity

The rocket reaches the top when

v_y =0

So by substituting into the equation, we find the time t at which this happens:

t=-\frac{u_y}{g}=-\frac{60.2}{-9.8}=6.14 s

7 0
3 years ago
A hockey puck has a mass of 0.107 kg and is at rest. A hockey player makes a shot, exerting a constant force of 28.0 N on the pu
gregori [183]

Answer:

The speed does it head toward the goal = 41.87 \frac{m}{s}

Explanation:

Mass = 0.107 kg

Initial velocity ( u ) = 0

Force (F) = 28 N

Time = 0.16 sec

From newton's second law,  Force  = mass × acceleration

⇒  F = m × a

⇒  28 = 0.107 × a

⇒  a = 261.7 \frac{m}{s^{2} } --------- (1)

This is the value of acceleration.

Final speed of the mass is calculated by the equation V = U + at

⇒ U = 0 because mass in in rest position at start.

⇒ V = a t

Put the values of acceleration and time in above formula we get

⇒ V = 261.7 × 0.16

⇒ V = 41.87 \frac{m}{s}

Therefore the speed does it head toward the goal = 41.87 \frac{m}{s}

5 0
3 years ago
José and Laurel measured the length of a stick's shadow during the day. Without knowing the length of the stick, which of their
skelet666 [1.2K]

Answer:

Option B.

Explanation:

Assuming the stick is in vertical position, its shadow depends on two factors: its length and the angle between the sun rays and the stick. When the angle is bigger, the lenght of the shadow increases, and vice versa. So, when the sun rays are parallel to the stick, the shadow may be small. Since they are nearly perpendicular to the Earth's surface at 12 o'clock, the shadow of the stick at that time should be minimal. It means that the measured shadow of 75 cm at 12:30 p.m. is almost impossible (Option B).

5 0
3 years ago
A rock has a mass of 8.0 kilograms falls 5 meters.
Liono4ka [1.6K]

Answer:

A. 392J

B. 392J

C. 9.899m/s

Explanation:

3 0
3 years ago
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