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Daniel [21]
2 years ago
11

Question 1 of 10

Physics
2 answers:
ivanzaharov [21]2 years ago
6 0
The answer would be 46.482 because you multiply 18.3 by 2.54 because for every inch you get 2.54 centimeters
Anestetic [448]2 years ago
5 0

Answer:

46.482 cm

Explanation:

Since 1 in = 2.54cm\\\\18.3 inches =(18.3 x 2.54) cm\\                   =46.482cm

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A pendulum of 50 cm long consists of small ball of 2kg starts swinging down from height of 45cm at rest. the ball swings down an
Ket [755]

Assuming that all energy of the small ball is transferred to the bigger ball upon impact, then we can say that:

Potential Energy of the small ball = Kinetic Energy of the bigger ball

Potential Energy = mass * gravity * height

Since the small ball start at 45 cm, then the height covered during the swinging movement is only:

height = 50 cm – 45 cm = 5 cm = 0.05 m

Calculating for Potential Energy, PE:

PE = 2 kg * 9.8 m / s^2 * 0.05 m = 0.98 J

Therefore, maximum kinetic energy of the bigger ball is:

<span>Max KE = PE = 0.98 J</span>

5 0
3 years ago
Isaac Newton’s investigations of gravity explained which truth?
Darina [25.2K]
C. Gravity acts on all objects in the universe! 
8 0
3 years ago
At what location in a circuit is the electrical potential energy the greatest
Eduardwww [97]

It's not the potential energy.  It's just the potential.

It's greatest at the positive terminal of the battery or power supply.


4 0
3 years ago
A flare is launched from a life raft with an initial velocity of 192 ft/sec. How many seconds will it take for the flare to retu
DIA [1.3K]

We use the formula,

h= ut- 16 t^2

Here, h is the  variable  represents the height of the flare  in feet when it returns to the sea so, h = 0 and u is the initial velocity of the flare, in feet per second and its value of 192 ft/sec.

Substituting these values in above equation, we get

0 = 192 t - 16 t^2  \\\\ 16 t( 12 - t ) =0 \\\\ t = 12 s.

Here, t= 0 neglect because it is  the time when the flare is launched.

Thus, flare return to the sea in 12 s.

8 0
3 years ago
1 point<br> You throw a ball up in the air with a velocity of 30 m/s. How high does it<br> go?
choli [55]

Answer:

Explanation:

2as=vf^2-Vi^2

vf=30 m/s

vi= 0 m/s

a=g=9.8 m/s^2

s=vf^2-Vi^2/2a

s=(30)²-(0)²/2*9.8

s=900-0/19.6

s=45.9=46 m

4 0
3 years ago
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