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3 years ago

A toy plane with a mass of 1.5 kg is flying in the air at 8.0 m/s. What is its kinetic energy?

Physics

2 answers:

natita [175]3 years ago

7 0

Answer:

KE=48J

Explanation:

You use the equation:

KE=1/2mv^2

KE=1/2(1.5kg)(8.0m/s)^2

KE=48J

Nikolay [14]3 years ago

5 0

Given : A toy plane has a mass of 1.5kg . It is flying in air at a speed of 8m/s .

To Find : The Kinetic energy of the plane .

Solution : The mass of the toy plane is 1.5kg and Velocity is 8.0 m / s . So we know the formula to find the kinetic energy as ,

$\boxed{\red{\bf Energy_{Kinetic}=\dfrac{1}{2}mv^2}}$

On substituting the respective values,

⇒ KE = ½mv².

⇒ KE = ½ × 1.5 kg × (8 m/s)².

⇒ KE = ½ × 1.5 kg × 64m²/s² .

⇒ KE = 48 J .

Hence the Kinetic energy of the plane is 48Joules.

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The magnetic field at the centre of a toroid is 2.2-mT. If the toroid carries a current of 9.6 A and has 6.000 turns, what is th

ziro4ka [17]

Answer:

Radius, r = 0.00523 meters

Explanation:

It is given that,

Magnetic field, $B=2\ mT=2.2\times 10^{-3}\ T$

Current in the toroid, I = 9.6 A

Number of turns, N = 6

We need to find the radius of the toroid. The magnetic field at the center of the toroid is given by :

$B=\dfrac{\mu_oNI}{2\pi r}$

$r=\dfrac{\mu_oNI}{2\pi B}$

$r=\dfrac{4\pi \times 10^{-7}\times 6\times 9.6}{2.2\pi \times 2\times 10^{-3}}$

r = 0.00523 m

$r=5.23\times 10^{-3}\ m$

So, the radius of the toroid is 0.00523 meters. Hence, this is the required solution.

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3 years ago

Read 2 more answers

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LenaWriter [7]

Answer:

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3 years ago

Paula has walked in a straight line, 30.5° north of west, for 1650 meters. How far south and east should she walks to return to

olchik [2.2K]

The answer is A.
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8 0

3 years ago

Is a spring stores 5 J of energy when its conpresses by 0.5 m what is the spring constant of the spring?

d1i1m1o1n [39]

Answer:

k = 40 N/m

Explanation:

A spring's energy is given:

$U = 0.5kx^2$

U is the energy in the spring, k is the spring constant and x is the spring displacement.

We are told that the spring stores 5J of energy, therefore, U = 5J. We are also told that the spring is compressed by 0.5m, so the spring x = 0.5m

$5 J = 0.5k(0.5m)^2\\5J = 0.5k(0.25m^2)\\5J = k*(0.125)m^2\\\\k = 5J/(0.125)m^2\\k = 40 N/m$

k = 40 N/m

Hope this helps!

3 0

4 years ago

Who water rocket starts from rest and roses straight up with an acceleration of 5 m/s until it runs out of water 2.5 seconds lat

Kitty [74]

Answer:

23. 4375 m

Explanation:

There are two parts of the rocket's motion

1 ) accelerating (assume it goes upto h1 height )

using motion equations upwards

$s = ut+\frac{1}{2}*a*t^{2} \\h_1=0+\frac{1}{2}*5*2.5^{2} \\=15.625 m$

Lets find the velocity after 2.5 seconds (V1)

V = U +at

V1 = 0 +5*2.5 = 12.5 m/s

2) motion under gravity (assume it goes upto h2 height )

now there no acceleration from the rocket. it is now subjected to the gravity

using motion equations upwards (assuming g= 10m/s² downwards)

V²= U² +2as

0 = 12.5²+2*(-10)*h2

h2 = 7.8125 m

maximum height = h1 + h2

= 15.625 + 7.8125

= 23. 4375 m

3 0

3 years ago