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LenKa [72]
3 years ago
5

A toy plane with a mass of 1.5 kg is flying in the air at 8.0 m/s. What is its kinetic energy?

Physics
2 answers:
natita [175]3 years ago
7 0

Answer:

KE=48J

Explanation:

You use the equation:

KE=1/2mv^2

KE=1/2(1.5kg)(8.0m/s)^2

KE=48J

Nikolay [14]3 years ago
5 0

Given : A toy plane has a mass of 1.5kg . It is flying in air at a speed of 8m/s .

To Find : The Kinetic energy of the plane .

Solution : The mass of the toy plane is 1.5kg and Velocity is 8.0 m / s . So we know the formula to find the kinetic energy as ,

\boxed{\red{\bf Energy_{Kinetic}=\dfrac{1}{2}mv^2}}

On substituting the respective values,

⇒ KE = ½mv².

⇒ KE = ½ × 1.5 kg × (8 m/s)².

⇒ KE = ½ × 1.5 kg × 64m²/s² .

⇒ KE = 48 J .

<em><u>Hence</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>Kineti</u></em><em><u>c</u></em><em><u> energy</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>plane</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>4</u></em><em><u>8</u></em><em><u>J</u></em><em><u>o</u></em><em><u>u</u></em><em><u>l</u></em><em><u>e</u></em><em><u>s</u></em><em><u>.</u></em>

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2 years ago
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A spring scale exerts a net force of 8.5 N on an object. What is the object's mass if it has an acceleration of
Amiraneli [1.4K]

Answer:

mass of the object is 2.18 kg

Explanation:

Given

Force (F) = 8.5 N = 8.5 kg.m/s^{2}

acceleration (a) = 3.9 m/s^{2}

Mass (m) = ?

We know that the newton's second law of motion gives the relation between mass of ab object. force acted upon and the amount the object is accelerated. It is expressed in the form of an equation:

F = ma

mass, m = F/a

               = \frac{8.5 kgms^{-2} }{3.9 ms^{-2} }

               = 2.18 kg

4 0
3 years ago
Consider a 40,000 km steel pipe in the shape of a ring that fits snuggly all around the circumference of the Earth. We are heati
Tatiana [17]

Answer:

The Height is  H = 70.02 m

Explanation:

We are given that the

                         Initial length is  = 40000\ Km = 40,000 *10^{3} m

from what we are told in the question the circumference of the circle is = 40,000 Km

  This means that the Radius would be :

         Let C denote the circumference

      So  

               C = 2 \pi r

      =>     r = \frac{C}{2 \pi}

               r = \frac{40,000}{2 \pi } = \frac{40,000*10^{3}}{2 *3.142}  = 6.365*10^6 m

We are told that 1-meter bar of steel that increases its temperature by 1 degree C will expand 11*10^{-6} meters

Hence

       The final length would be

                            40000*10^3 *(T + \alpha  )

Where T is the change in  temperature  \alpha is the Coefficient of linear expansion for steel

  let L_{final} denote the final length

   So

        L_{final} =40000*10^{6} *[1+ 11*10^{-6}]

                  = 40000440 \ m

 Now the Height is mathematically represented as

         Height(H) \ = \frac{change \ in \ radius \ }{2 \pi}

                       = \frac{(40000440-40000*10^3)}{2*3.142}

                       = 70.02m

3 0
3 years ago
A bomber is flying horizontally over level terrain at a speed of 280 m/s relative to the ground and at an altitude of 3.50 km. (
pychu [463]

Answer:

(a)7.48331 Km

(b) Directly above the tomb

(c) 12.53 degrees

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Using the formula

s=0.5gt^{2} where s is the distance and t is time, taking acceleration due to gravity as 9.8 then

3500 = 0.5*9.8*t^{2}

t = 26.72 sec

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Distance=Speed*time

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(b)directly above the bomb

(c) tan \theta = \frac {3500}{7483.31}

\theta = 12.53^{o}

8 0
2 years ago
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